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2 years ago

In a solution, which pair of actions could combine to keep a concentration constant?

Chemistry

1 answer:

insens350 [35]2 years ago

6 0

Answer:

B: Adding water, then adding solute

Explanation:

This is because, say you have a solution with a certain concentration.

If you add more water, it will become more diluted (less concentrated)

If you add more solute, it will become more concentrated.

Therefore if you add water and solute, it could cancel out, and the concentration would remain the same.

Hope this helps! Let me know if you have any questions/ would like anything further explained :)

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What is a graph?

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*Visual

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3 years ago

Which statement describes both homogeneous mixtures and heterogeneous mixtures?

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C. Their components can be separated by physical processes.

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3 years ago

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How many compounds, of the ones listed below, have hydrogen bonding? ch3(ch2)2nh2 ch3(ch2)2nh(ch2)4ch3 (ch3ch2)2n(ch2)4ch3?

Aloiza [94]

Answer:
Following two compounds have Hydrogen Bond Interactions;

1) CH₃(CH₂)₂NH₂ (Propan-1-amine)

2) CH₃(CH₂)₂NH(CH₂)₄CH₃ (N-propylpentan-1-amine)

Explanation:
Hydrogen Bond Interactions are formed between those molecules which has hydrogen atoms covalently bonded to most electronegative atoms like Fluorine, Oxygen and Nitrogen. This direct attachment of Hydrogen to electronegative atom makes it partial positive resulting in hydrogen bonding with neighbor's partial negative most electronegative atom. So, in above selected compounds it can be seen that both compounds contain hydrogen atoms directly attached to Nitrogen atoms, Therefore, allowing them to form Hydrogen Bonding Interactions.

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3 years ago

Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu

Monica [59]

Answer: The volume of the 1.224 M NaOH solution needed is 26.16 mL

Explanation:

In order to prepare the dilute NaOH solution, solvent is added to a given amount of the NaOH stock solution up to a final volume of 250.0 mL.

Since only solvent is added, the amount of the solute, NaOH, in the dilute solution is the same as in the volume taken from the stock solution.

Molarity (M) is calculated from the following equation:

M = n ÷ V

where n is the number of moles of the solute in the solution, and V is the volume of the solution.

Accordingly, the number of moles of the solute is given by

n = M x V

Now, let's designate the stock NaOH solution and the dilute solution as (1) and (2), respectively . The number of moles of NaOH in each of these solutions is:

n (1) = M (1) x V (1)

n (2) = M (2) x V (2)

As the amount of NaOH in the dilute solution is the same as in the volume taken from the stock solution,

n (1) = n (2)

and

M (1) x V (1) = M (2) x V (2)

For the stock solution, M (1) = 1.244 M, and V (1) is the volume needed. For the dilute solution, M (2) = 0,1281 M, and V (2) = 250.0 mL.

The volume of the stock solution needed, V (1), is calculated as follows:

V (1) = M (2) x V (2) ÷ M (1)

V (1) = 0.1281 M x 250.0 mL ÷ 1.224 M

V (1) = 26.16 mL

The volume of the 1.224 M NaOH solution needed is 26.16 mL.

7 0

2 years ago

A gold nugget has a density of 38.6g/cm3 and a mass of 270.2. what is its volume?

aivan3 [116]

Density is given by the equation D=m/V, were D is density, m is mass in grams, and V is volume in cubic centimeters.

In this problem, we have density and we have mass so we can plug into the equation and solve for V.

38.6=270.2/V

*Multiply both sides by V*

38.6V=270.2

*Divide both sides by 38.6*

V=7

The volume of the gold nugget is 7cm3.

Hope this helps!!

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3 years ago

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