Ok, my favorite is turning lights off when not in use OR changing out old lightbulbs that are more efficient. :)
Answer: The average valence electron energy (AVEE) of this element =
1014.2 KJ/ mol or 1.0142mJ/mol.
Explanation:
The average valence electron energy = (number of electrons in s subshell x Ionization energy of that subshell) + (number of electrons in p subshell x Ionization energy of that subshell) / total number of electrons in both subshells of the valence shells.
The 5A elements are non-metals like Nitrogen and Phosphorus with the metallic character increasing as you go down the group, So a new 5A element will have characteristics of its group with 5 valence electron in its outermost shell represented as ns2 np3
Therefore the average valence electron energy (AVEE) of this element will be calculated as
The average valence electron energy = (2 x 1370 kJ/mol + 3 x 777 kJ/mol.) / 5
2740+2331/ 5 =5071/5
=1014.2 KJ/ mol or 1.0142mJ/mol.
Answer:
Strong acids are assumed 100% dissociated in water- True
As a solution becomes more basic, the pOH of the solution increases- false
The conjugate base of a weak acid is a strong base- true
The Ka equilibrium constant always refers to the reaction of an acid with water to produce the conjugate base of the acid and the hydronium ion- True
As the Kb value for a base increases, base strength increases- true
The weaker the acid, the stronger the conjugate base- true
Explanation:
An acid is regarded as a strong acid if it attains 100% or complete dissociation in water.
The pOH decreases as a solution becomes more basic (as OH^- concentration increases).
Ka refers to the dissociation of an acid HA into H3O^+ and A^-.
The greater the base dissociation constant, the greater the base strength.
The weaker an acid is, the stronger , its conjugate base will be.
Answer: D.) 25.9%
Explanation:
Dinitrogen pentoxide chemical formular : N2O5
Calculating the molar mass of N2O5
Atomic mass of nitrogen(N) = 14
Atomic mass of oxygen(O) = 16
Therefore molar mass :
N2O5 = (2 × 14) + (5 × 16) = 28 + 80 = 108g/mol
Percentage amount of elements in N205:
NITROGEN (N) :
(Mass of nitrogen / molar mass of N2O5) × 100%
MASS OF NITROGEN = (N2) = 2 × 14 = 28
PERCENT OF NITROGEN : (28/108) × 100%
0.259259 × 100%
= 25.925%
= 25.9%
