Answer:
The amount of energy transferred to the water is 4.214 J
Explanation:
The given parameters are;
The mass of the object that drops = 5 kg
The height from which it drops = 86 mm (0.086 m)
The potential energy P.E. is given by the following formula
P.E = m·g·h
Where;
m = The mass of the object = 5 kg
g = The acceleration de to gravity = 9.8 m/s²
h = The height from which the object is dropped = 0.086 m
Therefore;
P.E. = 5 kg × 9.8 m/s² × 0.086 m = 4.214 J
Given that the potential energy is converted into heat energy, that raises the 1 g of water by 1°C, we have;
The amount of energy transferred to the water = The potential energy, P.E. = 4.214 J.
Answer:
total weight of aggregate = 5627528 lbs = 2814 tons
Explanation:
we get here volume of space to be filled with aggregate that is
volume = 2000 × 48 × 0.5
volume = 48000 ft³
now filling space with aggregate of the density that is
density = 0.95 × 119.7
density = 113.72 lb/ft³
and dry weight of this aggregate is
dry weight = 48000 × 113.72
dry weight = 5458320 lbs
we consider here percent moisture is by weigh
so weight of moisture in aggregate will be
weight of moisture = 0.031 × 5458320
weight of moisture = 169208 lbs
so here total weight of aggregate is
total weight of aggregate = 5458320 + 169208
total weight of aggregate = 5627528 lbs = 2814 tons
Why 1+12+ Y3 < 1100
Says the state of university Need to purchase 1100 computers in total, we have the following answer on the way top
Answer:
The work of the cycle.
Explanation:
The area enclosed by the cycle of the Pressure-Volume diagram of a Carnot engine represents the net work performed by the cycle.
The expansions yield work, and this is represented by the area under the curve all the way to the p=0 line. But the compressions consume work (or add negative work) and this is substracted fro the total work. Therefore the areas under the compressions are eliminated and you are left with only the enclosed area.
