Answer:
Shearing strain will be 0.1039 radian
Explanation:
We have given change in length ![\Delta L=0.12inch](https://tex.z-dn.net/?f=%5CDelta%20L%3D0.12inch)
Length of the pad L = 1.15 inch
We have to find the shearing strain
Shearing strain is given by
![\alpha =tan^{-1}\frac{\Delta L}{L}=tan^{-1}\frac{0.12}{1.15}=5.9571^{\circ}](https://tex.z-dn.net/?f=%5Calpha%20%3Dtan%5E%7B-1%7D%5Cfrac%7B%5CDelta%20L%7D%7BL%7D%3Dtan%5E%7B-1%7D%5Cfrac%7B0.12%7D%7B1.15%7D%3D5.9571%5E%7B%5Ccirc%7D)
Shearing strain is always in radian so we have to change angle in radian
So ![5.9571\times \frac{\pi }{180}=0.1039radian](https://tex.z-dn.net/?f=5.9571%5Ctimes%20%5Cfrac%7B%5Cpi%20%7D%7B180%7D%3D0.1039radian)
Answer:
skskkdkdkfkgkgkgkkgkgkgigooigigi lol
Explanation:
Oof
Answer:
enables the representation, analysis and communication of various aspects of an information system. These aspects correspond to varying and incomplete views of information systems and the processes therein.
Answer:
C = 292 Mbps
Explanation:
Given:
- Signal Transmitted Power P = 250mW
- The noise in channel N = 10 uW
- The signal bandwidth W = 20 MHz
Find:
what is the maximum capacity of the channel?
Solution:
-The capacity of the channel is given by Shannon's Formula:
C = W*log_2 ( 1 + P/N)
- Plug the values in:
C = (20*10^6)*log_2 ( 1 + 250*10^-3/10)
C = (20*10^6)*log_2 (25001)
C = (20*10^6)*14.6096
C = 292 Mbps
Answer:
See explanation
Explanation:
The magnetic force is
F = qvB sin θ
We see that sin θ = 1, since the angle between the velocity and the direction of the field is 90º. Entering the other given quantities yields
F
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