A vacuum gage connected to a tank reads 30 kPa at a location where the barometric reading is 755 mmHg. Determine the absolute pr
1 answer:
Answer:
Absolute pressure=70.72 KPa
Explanation:
Given that Vacuum gauge pressure= 30 KPa
Barometer reading =755 mm Hg
We know that barometer always reads atmospheric pressure at given situation.So atmospheric pressure is equal to 755 mm Hg.
We know that P= ρ g h
Density of
So P=13600 x 9.81 x 0.755
P=100.72 KPa
We know that
Absolute pressure=atmospheric pressure + gauge pressure
But here given that 30 KPa is a Vacuum pressure ,so we will take it as negative.
Absolute pressure=atmospheric pressure + gauge pressure
Absolute pressure=100.72 - 30 KPa
So
Absolute pressure=70.72 KPa
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Answer:
hello your question incomplete attached below is the complete question and detailed solution
Answer : Csf = 0.0131
Explanation:
Attached below is the detailed solution
Given data :
ΔTe = 17.1⁰c calculated as ;Ts - Tsat = ( 117.1 - 100 )
Pe = 957.9 kg/m^3
Cp1e = 4217 j/kgk
<em>U</em>e = 279 * 10^-6 n. s / m^2
Pre = 1.76
hfg = 2.257 * 10^6 J/kg
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б = 0.0589 N/m
q" = 664 * 10^3 w/m^2 ( calculated )
Input these values into equation 1 as contained in the detailed solution
Csf = 0.0131
Answer:
Explanation:
First we should recall how Newton's laws relates shear stress to a fluid's velocity profile:
where tau is the shear stress, mu is viscosity, v is the fluid's velocity and y is the direction perpendicular to flow.
Now, in this case we have a parabolic velocity profile, and also we know that the fluid's velocity is zero at the boundary (no-slip condition) and that the vertex (maximum) is at and the velocity at that point is
We can put that in mathematical terms as:
From the no-slip condition, we can deduce that and so we are left with just two terms:
We know that the vertex is at and so we can rewrite the last equation as:
where k and h are constants to be determined. First we check that :
So we found that h was the maximum velocity for the fluid, now we have to determine k, for that we need to make use of the no-slip condition.
And thus we find that the final expression for the fluid's velocity is:
where v is in mm/s and y is in mm.
In SI units it would be:
To calculate the shear stress, we need to take the derivative of this expression and multiply by the fluid's viscosity:
for we have:
Which is our final result
Answer:
See explaination
Explanation:
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See attached file for detailed solution of the given problem.
