What alcohol is formed when the alkene is treated with h2o in the presence of h2so4? qs14?
1 answer:
Here we have to get the alcohols which are formed in the reaction of an alkene with H₂SO₄ and H₂O.
The alcohols which are formed in the reaction between alkene and H₂SO₄ and H₂O are majorly secondary and tertiary alcohol. As primary alcohol only ethanol can be produced in this reaction.
The addition of H₂SO₄/H₂O generates alcohol from alkene. The general reaction is shown in the figure. In this reaction methanol (CH₃OH) cannot be prepared and in primary alcohol only ethanol (C₂H₅OH) can be prepared from ethene.
In case of propene and other higher alkene always secondary or tertiary alcohols are produced as the addition of sulphuric acid and water depends on the Markonikov's rule of addition to the less hindered position.
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Answer:
Therefore 373 mole of Al produce 746 mole of water.
Explanation:
Given reaction is
3 Al+3NH₄ClO₄→Al₂O₃+AlCl₃+3NO+6H₂O
From the above reaction it is clear that 3 mole of Al produce 6 mole of water.
Therefore
3 mole of Al produce 6 mole of water.
1 mole of Al produce mole of water.
373 mole of Al produce mole of water.
= 746 mole of water.
Therefore 373 mole of Al produce 746 mole of water.