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ivann1987 [24]
2 years ago
15

If 25 ml of 1.50M LiOH are neutralized by 15ml of nitric acid what is the molarity of HNO3

Chemistry
2 answers:
Jobisdone [24]2 years ago
8 0
LiOH + HNO3 --> H2O + LiNO3
OH- + H+  --> H2O
OH - = 1.5M * .025L = .0375 mol
.0375mol/.04L = 0.9375M
Since it's at the equivalence point, OH- = H+ concentration

[HNO3] = 0.9375M
nasty-shy [4]2 years ago
8 0

Answer:

Ca = 2.5M

Explanation:

Volume of Acid (Va) = 15ml

Concentration of acid (Ca) = ?

Volume of base (Vb) = 25

Concentration of base (Cb) = 1.50M

The balanced chemical equation is given as;

LiOH + HNO3 --> LiNO3 + H2O

The formular relaing the parameters is given as;

(CaVa) / (CbVb) = Na/Nb

Where Na = Number of moles of Acid = 1

Nb = Number of moles of Base = 1

Making Ca subject of interest;

Ca = (Na * Cb * Vb) / (Nb * Va)

Ca = (1 * 1.50 * 25) / (1 * 15)

Ca = 37.5 / 15

Ca = 2.5M

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A sample of gas has a volume of 4.4 liters when the pressure is 3.3 atm. What is the volume when the pressure is reduced to 2.2
murzikaleks [220]
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WILL GIVE BRAINLIEST
seropon [69]

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Chemical reaction A, because the reactant is a compound

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3 0
2 years ago
Which of the following electron configurations describes an element that is a noble gas?
butalik [34]

Answer:

The answer to your question is: letter D.

Explanation:

Noble gases are located in group VIIIA of the periodic table, this means that they have 8 eight electrons in their outermost shell.

Due to this characteristic, they are stable and do not react with other elements.

a. 1s22s22p4    The outermost shell of this electron configuration has 6 electrons, then this element has 6 electrons not 8. This configuration is of an element of the group VIA.

b. [Ne]2s22p2  The outermost shell of this element has 4 electrons, so this is not the configuration of a noble gas.

c. [Ar] 3s1  This element only has one electron in its outermost shell, so this is the electron configuration of an alkaline metal.

d. 1s22s22p6 This element has 8 electrons in its outermost shell, so this is the electron configuration of a noble gas.

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Determine the bonding type for boron trihydride given the electronegativity on the Pauling scale for boron is 2.0 and for hydrog
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Explanation:

The type of bonding between the atoms forming a compound is determined by using the electronegativity difference between the atoms. According to the pauling's electronegativity rule:

  • If \Delta \chi=0, then the bond is non-polar.
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We are given:

Electronegativity for boron = 2.0

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\Delta \chi=\chi_{H}-\chi_{B}\\\\\Delta \chi=2.1-2.0=0.1

As, \Delta \chi is less than 1.7 and not equal to 0. Hence, the bond between boron and hydrogen is covalent bond.

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3 years ago
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