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OverLord2011 [107]
3 years ago
14

Solve: 3/8[-8 + 16 - (-2 and 1/2)]

Mathematics
1 answer:
Aliun [14]3 years ago
7 0

Answer:

63/16 or 3 15/16.

Step-by-step explanation:

Solve: 3/8[-8 + 16 - (-2 and 1/2)]  Using order of operations (PEMDAS):

=3/8[-8 + 16 - (-2.5)]

= 3/8( 8 + 2.5)

= 3/8(10.5)

= 31.5/8

= 63/16.

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In the diagram, ΔGHJ ≅ ΔSTU.
Anna007 [38]

Step-by-step explanation:

angle J is also 67 deg since the triangle is an isosceles triangle

angle T is 67 deg since the 2 triangles are congruent

angle G = 180 - 2x67 = 46 deg

ST is 5cm

HJ is 3.7cm

3 0
2 years ago
GEOMETRY-TRIG
Andrej [43]

Answer:

6. The distance Rampy Ronald would have travelled horizontally is approximately 48.428 feet for an actual maximum height of 21.486 feet

7. Rampy Ronald is going to make the jump

Please find attached the graph of the motion of Rampy Ronald, created with Microsoft Excel

Step-by-step explanation:

6. The given parameters are;

The width of the ravine = 80 ft

The inclination of the ramp with which Rampy Ronald will jump = 30°

The distance from the edge of the ravine the ramp ends = 5 feet

The speed with which Rampy Ronald will make the jump = 60 mph

The maximum height he will reach = 30 feet

Therefore, we have;

The height of the end of the ramp = 15 × sin(30°) = 7.5

The height of the end of the ramp = 7.5 feet

The height of the jump = 30 - 7.5 = 22.5

The vertical velocity = 60 × sin(30°) = 30

The vertical velocity = 30 mph

The horizontal velocity = 60 × cos(30°) = 30·√3

The horizontal velocity = 30·√3 mph

From the kinematic equation, v² = u² - 2gh, we have;

u² = 2gh

h = u²/2g = 900/(2 × 32.17405) ≈ 13.986

The maximum height reached 13.986 + 7.5 = 21.486

From v = u - gt

t = u/g = 30/32.17405 ≈ 0.932

t  ≈ 0.932 s

The distance Rampy Ronald would have travelled horizontally = 30·√3 × 0.932 ≈ 48.428

The distance Rampy Ronald would have travelled horizontally ≈ 48.428 feet

7. The time before Rampy Ronald reaches ground level again, is given by the following relation;

h = 1/2·g·t²

21.846 = 1/2 × 32.17405 × t²

t = √(21.846/16.087025) ≈ 1.165

t ≈ 1.366 s

The horizontal distance traveled is therefore;

The horizontal distance traveled from maximum height is 30·√3 × 1.165 ≈ 60.535

The horizontal distance traveled from maximum height is ≈ 70.979 feet

The total horizontal distance traveled ≈ 48.428 + 60.535 = 108.963

The total horizontal distance traveled ≈ 108.963 feet

The total horizontal distance required to make it across the ravine = 5 feet + 80 feet = 85 feet

Therefore, Rampy Ronald is going to make the jump

8 0
3 years ago
What is 31 billion in scientific notation? <br><br> explain clearly &lt;3 :D
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Answer:

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Step-by-step explanation:

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3 years ago
Nelson Middle School raised $19,950 on ticket sales for its carnival fundraiser last year at $15 per ticket. If the school sells
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Answer:

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Read 2 more answers
What is the average rate of change for 5/6 and 15/14
andreev551 [17]

Answer:

Average rate of change is <u>0.80.</u>

Step-by-step explanation:

Given:

The two points given are (5, 6) and (15, 14).

Average rate of change is the ratio of the overall change in 'y' and overall change in 'x'. If the overall change in 'y' is positive with 'x', then average rate of change is also positive and vice-versa.

The average rate of change for two points (x_1,y_1)\ and\ (x_2,y_2) is given as:

R=\frac{y_2-y_1}{x_2-x_1}

Plug in x_1=5,x_2=15,y_1=6,y_2=14 and solve for 'R'. This gives,

R= \frac{14-6}{15-5}\\\\R=\frac{8}{10}\\\\R=0.80

Therefore, the average rate of change for the points (5, 6) and (15, 14) is 0.80.

5 0
4 years ago
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