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densk [106]
3 years ago
7

What is the time required for an object starting

Physics
1 answer:
PtichkaEL [24]3 years ago
8 0
(3) 10.1 second Using equation of motion 500 = (0.5)(9.81)t^2. Rearranging, t = sqrt(1000/9.81) = 10.1s
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PE=30J, m=?, g=10m/s2, h=10m
OleMash [197]
Based on the given, this is probably a gravitational potential energy problem (PEgrav). The formula for PEgrav is:

PEgrav = mgh

Where:
m = mass (kg)
g = acceleration due to gravity
h = height (m)

With this formula you can derive the formula for your unknown, which is mass. First put in what you know and then solve for what you do not know.

PEgrav=mgh
30J=m(10)(10[tex] \frac{30}{100} =m)[/tex]

Do operations that you can with what is given first.

30J=m(100m)

Transpose the 100 to the other side of the equation. Do not forget that when you transpose, you do the opposite operation.

\frac{30}{100} =m

m = 0.30kg

5 0
3 years ago
Calculate the average induced voltage between the tips of the wings of an airplane flying above East Lansing at a speed of 885 k
Yakvenalex [24]

Answer:

=0.855V

Explanation:

The induced voltage can be calculated using below expression

E =B x dA/dt

Where dA/dt = area

B= magnetic field = 6.90×10-5 T.

We were given speed of 885 km/h but we will need to convert to m/s for consistency of unit

speed = 885 km/h

speed = 885 x 10^3 m/hr

speed = 885 x 10^3/60 x60 m/s

speed = 245.8 m/s

If The aircraft wing sweep out" an area

at t= 50.4seconds then we have;

dA/dt = 50.4 x 245.8

= 123388.32m^2/s

Then from the expression above

E =B x dA/dt substitute the values of each parameters, we have

E = 6.90 x 10^-5 x 12388.32 V

E =0.855V

Hence, the average induced voltage between the tips of the wings is =0.855V

6 0
2 years ago
can y'all please help me I really need you guys or just give me an idea or wrote the first paragraph please​
elixir [45]
Write about some struggles you’ve faced and what they can do to avoid those struggles. Maybe also what you personally learned from the struggle too.
7 0
2 years ago
How far will a rubber ball fall in 10 seconds
Olegator [25]

Answer:

490 meters

Explanation:

hope this helps!

5 0
3 years ago
A VCR that is not playing still uses 10.0 W of power. What is the current if the VCR is plugged into a 120 V electric outlet?
yuradex [85]

Answer:

0.08 ampere

Explanation:

Power = voltage x current

W = v x I

Given

Power = 10.0 w

V = 120v

I = ?

Therefore

10.0 = 120 x I

Divide both sides by by 120

10.0/120 = 120/120 x I

0.08 = I

I = 0.08 ampere

3 0
3 years ago
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