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densk [106]
3 years ago
7

What is the time required for an object starting

Physics
1 answer:
PtichkaEL [24]3 years ago
8 0
(3) 10.1 second Using equation of motion 500 = (0.5)(9.81)t^2. Rearranging, t = sqrt(1000/9.81) = 10.1s
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PLEASE HELP Which landforms can be associated with the three types of plate boundaries?
Margarita [4]
Convergent, divergent, and transform boundaries

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3 years ago
Which actions are essential to active participation? Check all that apply.
erastova [34]

Answer:

2, 3, 4, 6.

Explanation:

8 0
3 years ago
Read 2 more answers
which of these best dscribes Earth's mantle? A. most dense layer, consists of the outer and inner parts B. thinnest under the oc
stich3 [128]

C. middle layer, density increases with depth as pressure increases

Explanation:

The mantle is the middle layer of the earth. It's density increases with depth as pressure increases.

  • Based on the compositional division of the earth, our blue planet is divided into crust, mantle and the core.
  • The crust is the lightest and the outermost layer of the earth.
  • The mantle is the middle layer. Its density lies between that of the core and crust.
  • The mantle is the largest layer and density increases with depth here.
  • The core is a metallic ball. It is the most dense part of the earth.

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Mantle brainly.com/question/10758534

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6 0
3 years ago
The terminal speed of a sky diver is 130 km/h in the spread-eagle position and 326 km/h in the nosedive position. Assuming that
SIZIF [17.4K]

Answer:

\frac{A_{slow} }{A_{fast} }=6.2885

Explanation:

Given data

Terminal velocity for spread eagle position vt=130 km/h

Terminal velocity for nosedive position vt=326 km/h

The terminal speed of the diver is given by

v_{t}=\sqrt{\frac{2mg}{CpA} }

Therefore the area is given by

A=\frac{2mg}{Cp(v_{t})^{2}  }\\

Since everything else is constant in the two dives except for the terminal velocity, the ratio between the area in the slow position to the area in the fast position is

\frac{A_{slow} }{A_{fast} }=\frac{326^{2} }{130^{2} }\\\frac{A_{slow} }{A_{fast} }=6.2885

8 0
3 years ago
Evangelista Torricelli was the first person to realize that we live at the bottom of an ocean of air. He correctly surmised that
Radda [10]

Answer:

a)    h = 8.02 10³ m  b) yes

Explanation:

a) The pressure in a fluid is given by

      P = ρ g h

The pressure in this case is the atmospheric pressure, 1.013 105 Pa, let's clear the height (h)

      h = P / ρ g

      h = 1.013 10⁵ / (1.29 9.8)

      h = 8.02 10³ m

b) The height of Mount Everest is 8848 m

It is above this height, according to this model there would be no air to breathe

8 0
3 years ago
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