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OLEGan [10]
2 years ago
14

Identify the reactants and products and write chemical equations for each of the following reactions: a. Gaseous chlorine reacts

with an aqueous solution of potassium bromide to form liquid bromine and an aqueous solution of potassium chloride. b. Solid aluminum reacts with solid iodine to produce solid aluminum iodide. c. Solid magnesium reacts with an aqueous solution of hydrochloric acid to form an aqueous solution of magnesium chloride and bubbles of hydrogen gas.
Chemistry
1 answer:
Aneli [31]2 years ago
6 0

Answer:

a. Cl (g) + KBr (aq) = Br (l) + KCl (aq)

b. Al (s) + I (s) = AlI (s)

c. Mg (s) + HCl (aq) = MgCl (aq) + H2 (g)

Explanation:

The reactants are the elements before the equals sign and the products are the ones after the equals sign that are bolded.

Hope this helps :)

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riadik2000 [5.3K]

Answer:

A hydrocarbon is any of a class of organic chemicals made up of only the elements carbon (C) and hydrogen (H). The carbon atoms join together to form the framework of the compound, and the hydrogen atoms attach to them in many different configurations

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PLEASE HELP <br> What is the element dot structure for Li+1? Really confused about the +1 part.
AleksandrR [38]

Since it's Li+1, that means it's a Lithium ion, not just the element itself. The +1 charge means it loses an electron. The dot structure would be Lithium, and however many valence electrons it has minus 1

5 0
3 years ago
If 6.4 miles of Fe react with excess O2, how many miles of Fe2O3 can be formed? 4 Fe + 3 O2 -&gt; 2 Fe2O3
Yuri [45]
I'm assuming that by "miles" you mean moles.

If O2 is the excess reactant, that means Fe is the limiting reactant. That means that the amount of product being formed depends on the amount of Fe reactant present. To calculate the moles of Fe2O3 formed, start with the given 6.4 moles of Fe and use the mole to mole ratio given by the reaction as shown below:

6.4 mol Fe x \frac{2 mol Fe2O3}{4 mol Fe} = 3.2 mol Fe2O3
6 0
3 years ago
Hydrogen iodide decomposes according to the equation: 2HI(g) H 2(g) + I 2(g), K c = 0.0156 at 400ºC A 0.660 mol sample of HI was
Ira Lisetskai [31]

Answer:

[HI] = 0.264M

Explanation:

Based on the equilibrium:

2HI(g) ⇄ H₂(g) + I₂(g)

It is possible to define Kc of the reaction as the ratio between concentration of products and reactants using coefficients of each compound, thus:

<em>Kc = 0.0156 = [H₂] [I₂] / [HI]²</em>

<em />

As initial concentration of HI is 0.660mol / 2.00L = <em>0.330M, </em>the equlibrium concentrations will be:

[HI] = 0.330M - 2X

[H₂] = X

[I₂] = X

<em>Where X is reaction coefficient.</em>

<em />

Replacing in Kc:

0.0156 = [X] [X] / [0.330M - 2X]²

0.0156 = X² / [0.1089 - 1.32X + 4X² ]

0.00169884 - 0.020592 X + 0.0624 X² = X²

0.00169884 - 0.020592 X - 0.9376 X² = 0

Solving for X:

X = - 0.055 → False solution, there is no negative concentrations

X = 0.0330 → Right solution.

Replacing in HI formula:

[HI] = 0.330M - 2×0.033M

<h3>[HI] = 0.264M</h3>

7 0
3 years ago
What is the correct name for Mn(NO3),
kupik [55]

Answer:

Manganese trinitrate or manganese(III) nitrate

Explanation:

6 0
3 years ago
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