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OLEGan [10]
2 years ago
14

Identify the reactants and products and write chemical equations for each of the following reactions: a. Gaseous chlorine reacts

with an aqueous solution of potassium bromide to form liquid bromine and an aqueous solution of potassium chloride. b. Solid aluminum reacts with solid iodine to produce solid aluminum iodide. c. Solid magnesium reacts with an aqueous solution of hydrochloric acid to form an aqueous solution of magnesium chloride and bubbles of hydrogen gas.
Chemistry
1 answer:
Aneli [31]2 years ago
6 0

Answer:

a. Cl (g) + KBr (aq) = Br (l) + KCl (aq)

b. Al (s) + I (s) = AlI (s)

c. Mg (s) + HCl (aq) = MgCl (aq) + H2 (g)

Explanation:

The reactants are the elements before the equals sign and the products are the ones after the equals sign that are bolded.

Hope this helps :)

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Formula los siguientes compuesto: Dietil eter, Etanol, Propanotriol, Acido Propanodioico, Pentanal, Pentano-2,4-diona, Metanoato
9966 [12]

Answer:

Explanation:

En este caso para formular los compuestos, debes identificar el grupo funcional principal de la molecula. Una vez que eso está hecho, puedes intentar formularlo.

Empezaremos primero identificando el grupo funcional principal de la molécula, para luego formularlo correctamente.

Dietil eter: la terminación eter al final significa que pertenece al grupo de los éteres, el cual tiene como formula general R - O - R.

Etanol: debido a que termina en ol, este grupo pertenece a los alcoholes. Para formularlo solo se dibuja la molecula del etano, junto a un enlace con el grupo OH, como su formula general R - OH.

Propanotriol: igualmente termina en ol, por lo tanto es un alcohol, sin embargo, en este caso, tambien tiene la terminación prefija tri, asi que significa que hay 3 grupos OH en la molecula.

Acido propanodioico: esta es sencilla, porque empieza como acido, y solo hay un grupo funcional que empieza así y son los acidos carboxilicos, es decir, el grupo COOH (R - COOH) que es el carboxilo. Tiene el prefijo di, antes del oico, por lo que son dos carboxilos presentes en la molecula.

Pentanal: el sufijo al, significa que pertenece al grupo de los aldehidos, en este caso, posee el grupo carbonilo H - C = O.

Pentano - 2,4 - diona: la terminación ona significa que pertenece al grupo de las cetonas, (R - CO - R), parecido a los aldehidos, con la diferencia de que tiene grupos alquilos en lugar de un hidrogeno.

Metanoato de metilo: la terminación ato de ilo, pertenece a los esteres, (R - COOR) derivado de los acidos carboxilicos.

De aqui en adelante solo mencionaré los grupos funcionales pues ya se explicó el por que, por sus terminaciones:

Ciclohexano - 1.3 - diol: este pertenece a los alcoholes.

Acido heptanoico: acido carboxilico

Ciclobutil metil eter: eteres

Acetato de etilo: ester

2-metilbenzaldehído: aldehído unido a un grupo aromatico como el benceno.

Ciclohexanona: un ciclo (cadena cerrada) unido a un grupo carbonilo.

Butanona: cetona.

Observa la foto adjunta para que veas la formulación de cada una:

5 0
3 years ago
In a 10-gram sample of carbon and a 10-gram sample of sulfur, how many more moles of carbon are there than sulfur?
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Answer:

Here are three examples  

Explanation:

In a reversible reaction, the conversions of reactants to products and of products to reactants occur at the same time.

Example 1

The reaction of hydrogen and iodine to from hydrogen iodide.  

H₂ + I₂ ⇌ 2HI

Example 2

The dissociation of carbonic acid in water to form hydronium and hydrogen carbonate ions

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Example 3

The dissociation of dinitrogen tetroxide to nitrogen dioxide.

N₂O₄ ⇌ 2NO₂

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Missing question: 
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Oxygen: 3</span>.0 L; 2.0 atm; 25°C.
<span>When the valve between the two containers is opened, nitrogen gas moves from one container to another container and gases are mixed together, total volume of nitrogen is than:
V(nitrogen) = 2,0 L + 3,0 L = 5,0 L.</span>
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3 years ago
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Calculate the average bond order for a p−o bond (such as the one shown in blue) in a phosphate ion. express your answer numerica
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