system of equations means that we have a given number of equations with the same solutions.
If you only have tables, this means that you need to have one table for each equation:
For example, if you are working only with two variables, x and y, in those tables you can see the pints (x, y) that belong to each equation.
Now, a point (x, y) will be a solution of the system of equations only if it belongs to the data table for each equation
This would mean that if you graph those data sets, the graphs will intersect at the point (x, y) that belongs to all the tables of data.
another way may be using the data in the tables to construct the equations, but you said that you only want to use the tables, so this method can be discarded.
Answer:
Step-by-step explanation:
We can write two equations in the two unknowns using the given relations. Let g and b represent the costs of a round of golf and a turn in the batting cage, respectively.
5g +4b = 60 . . . . . Sylvester's expense
3g +6b = 45 . . . . . Lin's expense
Dividing the second equation by 3 gives ...
g +2b = 15 ⇒ 2b = 15 -g
Substituting into the first equation, we have ...
5g +2(2b) = 60
5g +2(15 -g) = 60 . . . . . substitute for 2b
3g = 30 . . . . . . . . . subtract 30, collect terms
g = 10 . . . . . . . divide by 3
__
2b = 15 -10 = 5 . . . . use the value of g to find b
b = 2.5 . . . . . . . . divide by 2
Mini golf costs $10 per round; batting cages cost $2.50 per turn.
Answer:
-12
Step-by-step explanation:
Your equation should be
$4(40 tickets) + $5(X) = $400
160 +5x = 400
-160 -160
0 5x = 340
divide both sides by 5
5x/5 = 340/5
x = 68
so they need to sell 68 tickets at the door.
4(40) + 5(68) = 400
160 + 340 + 400
400 + 400
