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nignag [31]
3 years ago
11

A biker starts from rest and reaches a speed of 10 m/s after t travelling with

Physics
2 answers:
yKpoI14uk [10]3 years ago
7 0

Answer:

v = u + at \\ v = 10 \: m. {s}^{ - 1}  \\ u = 0 \\ t = 5 \: s \\ a =  \frac{v - u}{t}  \\  =  \frac{10 - 0}{5}  =  \frac{10}{5}  \\  \therefore \: a = 2 \: m. {s}^{ - 2}

Natali [406]3 years ago
6 0

Answer:

2m/s^2

Explanation:

we can use this formula to get the answer:

(vf - vi) / t = a

Since vf= 10m/s, vi=0m/s, and t=5

We can just substitute the values into the formula to get the result

that is:

(10 - 0) / 5 = 2m/s^2

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Explanation:

7 0
3 years ago
A spherically-spreading EM wave comes from a 104.0 W source. At a distance of 9.6 m, what is the intensity of the wave?
Nookie1986 [14]

Answer:

Approximately 0.0898 W/m².

Explanation:

The intensity of light measures the power that the light delivers per unit area.

The source in this question delivers a constant power of \rm 104.0\; W. If the source here is a point source, that \rm 104.0\; W of power will be spread out evenly over a spherical surface that is centered at the point source. In this case, the radius of the surface will be 9.6 meters.

The surface area of a sphere of radius r is equal to 4\pi r^{2}. For the imaginary 9.6-meter sphere here, the surface area will be:

\rm 4\pi \times (9.6\; m)^{2} \approx 1158.12\; m^{2}.

That \rm 104.0\; W power is spread out evenly over this 9.6-meter sphere. The power delivered per unit area will be:

\displaystyle\rm  \frac{104.0\; W}{1158.12\; m^{2}}\approx 0.0898\; W\cdot m^{-2}.

8 0
3 years ago
The talk test can be used to measure the __________. A. knowledge of an activity B. intensity of an activity C. length of an act
marta [7]

Answer:

B.

Explanation:

According to CDC, if you’re doing moderate-intensity activity, you can talk but not sing during the activity.

8 0
4 years ago
Read 2 more answers
A mass of 2.50 kg is in a gravitational field of 14.0 N/kg. What force acts on the mass?
Olenka [21]
To determine the force that acts on the mass, just multiply the mass by the gravitational field. Using the given data,
                             F = (2.50 kg)(14 N/kg) = 35 N
Therefore, the force that acts on the mass is equal to 35 N. 
7 0
3 years ago
Read 2 more answers
A proton, starting from rest, accelerates through a potential difference of 1.0 kV and then moves into a magnetic field of 0.040
Minchanka [31]

Answer:

r = 0.11 m

Explanation:

The radius of the proton's resulting orbit can be calculated equaling the force centripetal (Fc) with the Lorentz force (F_{B}), as follows:

F_{c} = F_{B} \rightarrow \frac{m*v^{2}}{r} = qvB (1)

<u>Where:</u>

<em>m: is the proton's mass =  1.67*10⁻²⁷ kg</em>

<em>v: is the proton's velocity</em>

<em>r: is the radius of the proton's orbit</em>

<em>q: is the proton charge = 1.6*10⁻¹⁹ C</em>

<em>B: is the magnetic field = 0.040 T </em>

Solving equation (1) for r, we have:

r = \frac{mv}{qB}   (2)

By conservation of energy, we can find the velocity of the proton:

K = U \rightarrow \frac{1}{2}mv^{2} = q*\Delta V   (3)

<u>Where:</u>

<em>K: is kinetic energy</em>

<em>U: is electrostatic potential energy</em>

<em>ΔV: is the potential difference = 1.0 kV </em>

Solving equation (3) for v, we have:

v = \sqrt{\frac{2q\Dela V}{m}} = \sqrt{\frac{2*1.6 \cdot 10^{-19} C*1.0 \cdot 10^{3} V}{1.67 \cdot 10^{-27} kg}} = 4.38 \cdot 10^{5} m/s  

Now, by introducing v into equation (2), we can find the radius of the proton's resulting orbit:

r = \frac{mv}{qB} = \frac{1.67 \cdot 10^{-27} kg*4.38 \cdot 10^{5} m/s}{1.6 \cdot 10^{-19} C*0.040 T} = 0.11 m

Therefore, the radius of the proton's resulting orbit is 0.11 m.

I hope it helps you!  

5 0
3 years ago
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