Answer:
The average rate of energy transfer to the cooker is 1.80 kW.
Explanation:
Given that,
Pressure of boiled water = 300 kPa
Mass of water = 3 kg
Time = 30 min
Dryness friction of water = 0.5
Suppose, what is the average rate of energy transfer to the cooker?
We know that,
The specific enthalpy of evaporate at 300 kPa pressure
We need to calculate the enthalpy of water at initial state
We need to calculate the enthalpy of water at final state
Using formula of enthalpy
Put the value into the formula
We need to calculate the rate of energy transfer to the cooker
Using formula of rate of energy
Put the value into the formula
Hence, The average rate of energy transfer to the cooker is 1.80 kW.
Answer:
The correct option is (C).
Explanation:
Electric current can be direct or alternating.
The direct current flows only in one direction. It is unidirectional.
The alternating current or an C current reverse its direction periodically.
So, the correct statement regarding the alternating current is (c) i.e. Electrons reverse direction periodically.
Lower frequency waves have less strength to penetrate. How bad a wave is all depends on how well it penetrates our bodies. Visible light doesn't penetrate ur skin, but UV rays (higher than visible) can go through our skin, making it <span>bad" for us. High frequency waves have more energy and move faster</span>
Answer:
Explanation:
a = -g = -9.80 m/s squared
d o = 0
v o = 0
t = 1.8s
<h3>unkown:</h3>
d = ?
v = ?
Answer:
a) 298.5 nm
, 522.4 nm and b) radiation frequency does not change
Explanation:
When electromagnetic radiation reaches a medium with a different index of refraction, the medium vibrates the molecules, as if it were a resonance process, whereby the medium vibrates at the same frequency as the incident light.
On the other hand, when the light reaches another medium its average speed within the medium changes, it is now less than the speed of light in a vacuum (c) for this to happen as we saw that the frequency is constant there must be a change in the wavelength of the radiation that is characterized by the ratio
λₙ = λ₀ / n
λₙ = 400 nm in the void
λₙ = 400 / 1.34
λₙ= 298.5 nm
λ₀ = 700 nm
λₙ = 700 / 1.34
λₙ = 522.4 nm
The radiation frequency does not change
