a wire with mass per unit length 75 g/m runs horizontally at right angles to a uniform horizontal 0.12 T magnetic field. what am
1 answer:
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Answer:
P=(2 nm, 8mn)
Explanation:
Given :
Position of positively charged particle at origin,
Position of desired magnetic field,
Magnitude of desired magnetic field,
Let q be the positive charge magnitude placed at origin.
<u>We know the distance between the two Cartesian points is given as:</u>
<u>For the electric field effect to be zero at point D we need equal and opposite field at the point.</u>
as we know that the electric field lines emerge radially outward of a positive charge so the second charge will be at equally opposite side of the given point.
assuming that the second charge is placed at (x,y) nano-meters.
Therefore,
and
Answer:
a . 0.35cm
b. 11.33cm
Explanation:
a. Given both currents are in the same direction, the null point lies in between them. Let x be distance of N from first wire, then distance from 2nd wire is 4-x
#For the magnetic fields to be zero,the fields of both wires should be equal and opposite.They are only opposite in between the wires:
Hence, for currents in same direction, the point is 0.35cm
b. Given both currents flow in opposite directions, the null point lies on the other side.
#For the magnetic fields to be zero,the fields of both wires should be equal and opposite.They are only opposite in outside the wires:
Let x be distance of N from first wire, then distance from 2nd wire is 4+x:
Hence, if currents are in opposite directions the point on x-axis is 11.33cm