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Semenov [28]
3 years ago
15

A plastic ball with a volume of 19.7cm^3 has a mass of 15.8g Would this ball sink or float in a container of gasoline?

Chemistry
1 answer:
katrin [286]3 years ago
6 0

Answer:

It would sink because the density of the ball, 0.802 g/cm3, is greater than the density of gasoline.

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What is the urinary system and what does it do
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The urinary system filters and gets rid of waste from the body.
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Find the mass of 1 atom of Chlorine in gram.
vazorg [7]
B. 35.45 ! Hope this helps
6 0
3 years ago
In a fluorine atom, on which energy level are the valence electrons found?
aivan3 [116]

Answer:

second energy level

Explanation:

Valence electrons are those electrons which are present in outer most orbital of the atom.

This can be easily found through the electronic configuration of atom.

Electronic configuration of F:

F₉ = 1s² 2s² 2p⁵

We can see that the valence electrons are present in second energy level of F atom.

There are seven valence electrons of fluorine.

It is called halogens.

Halogens are very reactive these elements can not be found free in nature. Their boiling points also increases down the group which changes their physical states. i.e fluorine is gas while iodine is solid.

Fluorine:

1. it is yellow in color.

2. it is flammable gas.

3. it is highly corrosive.

4. fluorine has pungent smell.

5. its reactions with all other elements are very vigorous except neon, oxygen, krypton and helium.  

6 0
3 years ago
What is the density of a gas at STP that has a molar mass of 50.0 g/mol?
Flura [38]

Answer:

2.232 g/L

Explanation:

Assuming 1 mol, volume at STP is 22.4 L so you simply divide 50g by 22.4 L to get density

4 0
3 years ago
The K w for water at 0 ∘ C is 0.12 × 10 − 14 M 2 . Calculate the pH of a neutral aqueous solution at 0 ∘ C . p H = Is a pH = 7.2
Karo-lina-s [1.5K]

Answer:

pH → 7.46

Explanation:

We begin with the autoionization of water. This equilibrium reaction is:

2H₂O  ⇄   H₃O⁺  +  OH⁻            Kw = 1×10⁻¹⁴         at 25°C

Kw = [H₃O⁺] . [OH⁻]

We do not consider [H₂O] in the expression for the constant.

[H₃O⁺] = [OH⁻] = √1×10⁻¹⁴   →  1×10⁻⁷ M

Kw depends on the temperature

0.12×10⁻¹⁴ = [H₃O⁺] . [OH⁻]  → [H₃O⁺] = [OH⁻]         at 0°C

√0.12×10⁻¹⁴ = [H₃O⁺] → 3.46×10⁻⁸ M

- log [H₃O⁺] = pH

pH = - log 3.46×10⁻⁸ → 7.46

8 0
3 years ago
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