Based on our knowledge of strong and weak acids, we can confirm that the Ka value for acetic acid will be relatively low since it is a weak acid.
Acids can be strong or weak. This is determined by its <u><em>tendency to break apart into ions or stay together to form molecules.</em></u> Although somewhat counter-intuitive, strong acids are those that are most likely to break apart and therefore contain a <em><u>high number of </u></em><em><u>ions </u></em><em><u>within their solutions</u></em>.
Weak acids, on the other hand, are those that<em><u> tend to stay together in the form of </u></em><em><u>molecules </u></em><em><u>and therefore possess very </u></em><em><u>low ion counts </u></em><em><u>in their solutions.</u></em> The acid dissociation constant, Kₐ, is used to measure whether an acid is weak or strong and how much so. In the case of Acetic acid, the ka measurement will offer a low value, indicating a weak acid.
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Complete Question
Magnesium sulfate forms a hydrate with the formula
. What is the maximum amount of water (in grams) that can be removed from 15 ml of toluene by the addition of 200 mg of anhydrous magnesium sulfate? The molar mass of
is 120.4 g/mol; H20 = 18 g/mol.
Answer:
The value is
of
Explanation:
From the question we are told that
The volume of toluene is 
The mass of anhydrous magnesium sulfate is 
The formula of the hydrate is 
The molar mass of
is 
From the formula given we see that
1 mole of
wil remove 7 moles of
to for the given formula
Hence
120.4 g (1 mole) will remove 7 moles (7 * 18 g = 126 g ) of
to for the given formula
Therefore 1 g of
x g of
So
![x = \frac{x]126 * 1}{ 120.4 }](https://tex.z-dn.net/?f=x%20%20%3D%20%20%5Cfrac%7Bx%5D126%20%2A%20%201%7D%7B%20120.4%20%7D)
=> 
From our calculation we obtained that
1 g of
will remove
of
Then
of
will remove z g of
of
So

=>
=>
of
The solution would be like this for this specific problem:
<span>Given:
</span>66.0 g of carbon monoxide
reaction 2 C + O2 → 2 CO
<span>mol e= mass / molar mass <span>
<span>mole of 2CO = 66.0g / (12.011 15.999)g / mol </span>
mole of 2CO = 2.36 (CO and C has a 1:1 mole ratio)
mole of 2CO = 2.36 -> mole of 1 CO = 2.36 / 2 = 1.18
<span>We got 2 moles of C, thus 1.18 x 2 = 2.36
So, we 2.36 </span>moles of carbon are needed to produce 66.0 g of carbon monoxide in the </span>reaction
2 C + O2 → 2 CO.</span>
<span>To add, Carbon nonmetallic
and tetravalent, thus, making four electrons available to form covalent
chemical bonds. </span>