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3 years ago

I'll mark the brainliest who will answer this answer correct.

Mathematics

1 answer:

slega [8]3 years ago

7 0

Answer:

Convert the following into rupees and paise.

a. 300paise = 3 Rupees 0 paise

b. 705paise = 7 Rupees 5 paise

c. 3260paise = 32 Rupees 60 paise

d. 5275paise = 52 Rupees 75 paise

e. 8265paise = 82 Rupees 65 paise

f. 9305paise = 93 Rupees 5 paise

g. 6010paise = 60 Rupees 10 paise

h. 7995paise = 79 Rupees 95 paise

i. 2335paise = 23 Rupees 35 paise

j. 1175 paise = 11 Rupees 75 paise

k. 425 paise = 4 Rupees 25 paise

l. 9090paise = 90 Rupees 90 paise

Hope it's helpful!

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P(k)=a^k=2 3 4 find value of a that makes this is a valid probability distribution

Vesna [10]

Sounds like you're asked to find $a$ such that

$\displaystyle\sum_{k=2}^4\mathbb P(k)=\mathbb P(2)+\mathbb P(3)+\mathbb P(4)=1$

In other words, find $a$ that satisfies

$a^2+a^3+a^4=1$

We can factorize this as

$a^4+a^3+a^2-1=a^3(a+1)+(a-1)(a+1)=(a+1)(a^3+a-1)=0$

In order that $\mathbb P(k)$ describes a probability distribution, require that $\mathbb P(k)\ge0$ for all $k$ , which means we can ignore the possibility of $a=-1$ .

Let $a=y+\dfrac xy$ .

$a^3+a-1=\left(y+\dfrac xy\right)^3+\left(y+\dfrac xy\right)-1=0$
$\left(y^3+3xy+\dfrac{3x^2}y+\dfrac{x^3}{y^3}\right)+\left(y+\dfrac xy\right)-1=0$

Multiply both sides by $y^3$ .

$y^6+3xy^4+3x^2y^2+x^3+y^4+xy^2-y^3=0$

We want to find $x\neq0$ that removes the quartic and quadratic terms from the equation, i.e.

$\begin{cases}3x+1=0\\3x^2+x=0\end{cases}\implies x=-\dfrac13$

so the cubic above transforms to

$y^6-y^3-\dfrac1{27}=0$

Substitute $y^3=z$ and we get

$z^2-z-\dfrac1{27}=0\implies z=\dfrac{9+\sqrt{93}}{18}$
$\implies y=\sqrt[3]{\dfrac{9+\sqrt{93}}{18}}$
$\implies a=\sqrt[3]{\dfrac{9+\sqrt{93}}{18}}-\dfrac13\sqrt[3]{\dfrac{18}{9+\sqrt{93}}}$

6 0

3 years ago

Algorithm to accept the height of a building in metres and convert it into centimetres.Also draw the flowchart

Anna11 [10]

Answer:

1200cm

Step-by-step explanation:

Given data

We know that 1meter is equivalent to 100cm

i,.e 1*100

so, if height is 1.2meters

Height in centimeters is 1.2*100

Hence height in centimeters is 1200cm

4 0

3 years ago

Quadrilateral ABCD is the result of a translation of quadrilateral EFGH. Segment EF is parallel to segment HG in the pre-image.

Mazyrski [523]

The correct answer:
The corresponding segments BC and AD in the image are parallel

3 0

4 years ago

Read 2 more answers

8. Nate bought two large pizzas and one small pizza and paid $36. If the difference in cost between a large and small pizza is $

s344n2d4d5 [400]

Answer:

$8.5

Step-by-step explanation:

We need to propose a system of equations with the information provided to us.

two large pizzas and one small pizza cost $36:

$2L+S=36$

where

$L$ : Large pizza

$S:$ Small pizza

and the difference in cost between a large and small pizza is $5.25:

$L-S=5.25$

our system of equations is:

$2L+S=36$

$L-S=5.25$

We are asked for the price of small pizza, so we must manipulate the equations in such a way that adding or subtracting them removes the variable L and we are left with an equation for S.

Multiply the second equation of the system by -2

$(-2)(L-S=5.25)\\\\-2L+2S=-10.5$