2 years ago

If 39.0 g of MgSO4⋅7H2O is thoroughly heated, what mass of anhydrous magnesium sulfate will remain?

Chemistry

1 answer:

pashok25 [27]2 years ago

4 0

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Match the amount of reactants and products on both sides of the equation.

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Read 2 more answers

An empty container weighs 80.21 g. it is filled with 20.14 mL of an unknown liquid, and the total weight of the container and li

tatiyna

Answer:

1.242 g/mL

Explanation:

Step 1: Given data

Mass of the empty container (m₁): 80.21 g

Mass of the filled container (m₂): 105.22 g

Volume of the unknown liquid (V): 20.14 mL

Step 2: Calculate the mass of the liquid

The mass of the liquid is equal to the difference between the mass of the filled container and the mass of the empty container.

$m = m_2 - m_1 = 105.22g - 80.21 g = 25.01 g$

Step 3: Calculate the density of the unknown liquid

The density of the liquid is equal to its mass divided by its volume.

$\rho = \frac{m}{V} = \frac{25.01g}{20.14mL} = 1.242 g/mL$

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