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Bond [772]
2 years ago
10

Did I get these correctly?

Chemistry
1 answer:
Luda [366]2 years ago
4 0
Those are both correct! great job, keep up the good work (-:
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Calculate ΔHrxnΔHrxn for the following reaction: 3C(s)+4H2(g)→C3H8(l)3C(s)+4H2(g)→C3H8(l) Use the following reactions and given
mihalych1998 [28]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is -120.9 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

3C(s)+4H_2(g)\rightarrow C_3H_8(l)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) C_3H_8(l)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)    \Delta H_1=-2026.6kJ

(2) C(s)+O_2(g)\rightarrow CO_2(g)     \Delta H_2=-393.5kJ     ( × 3)

(3) 2H_2(g)+O_2(g)\rightarrow 2H_2O(g)     \Delta H_2=-483.5kJ     ( × 2)

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[1\times (-\Delta H_1)]+[3\times \Delta H_2]+[2\times \Delta H_3]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(1\times -(-2026.6))+(3\times (-393.5))+(2\times (-483.5))]=-120.9kJ

Hence, the \Delta H^o_{rxn} for the reaction is -120.9 kJ.

8 0
3 years ago
What is the product of aluminum +zinc sulfate solution
melamori03 [73]

Answer:

ZINC ALUMINATE

5 0
2 years ago
Which gas variable has to do with the amount of collisions of gas particles has?
Firlakuza [10]
The answer is temperature
3 0
3 years ago
A 25.00-mL aliquot of a nitric acid solution of unknown concentration is pipetted into a 125-mL Erlenmeyer flask and 2 drops of
Semenov [28]

Answer:

0.0611M of HNO3

Explanation:

<em>The concentration of the NaOH solution must be 0.1198M</em>

<em />

The reaction of NaOH with HNO3 is:

NaOH + HNO3 → NaNO3 + H2O

<em>1 mole of NaOH reacts per mole of HNO3.</em>

That means the moles of NaOH used in the titration are equal to moles of HNO3.

<em>Moles HNO3:</em>

12.75mL = 0.01275L * (0.1198mol / L) = 0.0015274 moles NaOH = Moles HNO3.

In 25.00mL = 0.025L -The volume of the aliquot-:

0.00153 moles HNO3 / 0.025L =

<h3> 0.0611M of HNO3</h3>
7 0
3 years ago
How does matter change phase?
crimeas [40]

Answer:

Phase changes typically occur when the temperature or pressure of a system is altered. When temperature or pressure increases, molecules interact more with each other. When pressure increases or temperature decreases, it's easier for atoms and molecules to settle into a more rigid structure.

Explanation:

Hope it helps UvU

7 0
2 years ago
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