Answer:
Explanation:
Hello there!
In this case, according to the given information, it is possible for us to realize this problem is about mole ratios. Thus, for the compound C4H10, note there is a 1:10 mole ratio to the hydrogen atoms, that is why the number of moles of the latter is calculated as shown below:
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<span>Fe(OH)3(S) +3HNO3(aq)----->Fe(NO3)3(aq) + 3H20(aq)
M(Fe(OH)3)=56+48+3=107; M(HNO3)= 48+14+1=63
n(Fe(OH)3)=5.4/107=0.05; n(HNO3)=2.6/63=0.04
n(Fe(OH)3):n(HNO3)=1:3, which means that the HNO3 should be three times (molar) than the Fe(OH)3, but you can see that it is, actually, even less than the Fe(OH)3, meaning that HNO3 is the limiting reagent and the amount of Fe(OH)3 which is going to react with HNO3 is 0.04/3=0.013 i.e. 0.05-0.013=0.037 mol Fe(OH)3 is left after the completion.
Just in case you can convert it into mass, but I suppose this is enough.</span>
Magnesium iodide = MgI₂
mass of Mg = 24.3g
mass of I = 126.9g
mass of MgI₂ = 24.3 + 2*126.9 = 278.1g = 1 mole
in 5.36x10⁻⁴ mole of MgI₂ ---------------- x g of Mg
in 1 mole of MgI₂ ------------------------------ 1 mole of Mg
x = 5.36x10⁻⁴ moles of Mg = 0.000536 moles of Mg
answer: we've 0.000536 moles of Mg (magnesium ions) in 5.36x10⁻⁴ moles of MgI₂
If countries are on plate boundaries, such as Japan, they are more prone to earthquakes. If countries are above hot spots, such as Hawaii, they are more prone to volcanoes.
Answer : The percentage aniline protonated is, 0.0209 %
Explanation :
First we have to calculate the pOH.
Now we have to calculate the hydroxide ion concentration.
![pOH=-\log [OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%20%5BOH%5E-%5D)
![5.68=-\log [OH^-]](https://tex.z-dn.net/?f=5.68%3D-%5Clog%20%5BOH%5E-%5D)
![[OH^-]=2.09\times 10^{-6}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D2.09%5Ctimes%2010%5E%7B-6%7DM)
The equilibrium chemical reaction will be:
From the reaction we conclude that,
Concentration of 
ion = Concentration of 
ion = 
Now we have to calculate the percentage aniline protonated.
Thus, the percentage aniline protonated is, 0.0209 %
