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Mice21 [21]
3 years ago
10

Suppose Highlinium-308 can also undergo positron emission

Chemistry
1 answer:
____ [38]3 years ago
4 0

Answer:

The atomic number of burienium will be 307.

Explanation:

During positron emission proton is converted into the neutron and one electron neutrino with positron is released. It means the atomic number will be reduce by one and atomic mass remain same.

For example:

²³Mg₁₂    →     ₁₁Na²³+ e⁺+ Ve

Similarly, when highlinium-308 undergoes positron emission the new element burienium is produced and the atomic number will be 307 while atomic mass remain same.

Properties of beta radiations:

Beta radiations are result from the beta decay in which electron is ejected. The neutron inside of the nucleus converted into the proton an thus emit the electron which is called β particle.

The mass of beta particle is smaller than the alpha particles.

They can travel in air in few meter distance.

These radiations can penetrate into the human skin.

The sheet of aluminium is used to block the beta radiation

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Using the balanced reaction below, drag and drop the terms into the correct location to solve the following problem:
k0ka [10]

Answer:

4.5 moles of H2O.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

C2H5OH + 3O2 —> 2CO2 + 3H2O

From the balanced equation above,

1 moles of C2H5OH reacted to produce 3 moles of H2O.

Finally, we shall determine the number of mole of H2O produced by the reaction of 1.5 moles of C2H5OH. This can be obtained as follow:

From the balanced equation above,

1 moles of C2H5OH reacted to produce 3 moles of H2O.

Therefore, 1.5 moles of C2H5OH will react to produce = 1.5 × 3/ 1 = 4.5 moles of H2O.

Thus, 4.5 moles of H2O will be produced.

6 0
3 years ago
WILL GIVE BRAINLIEST ANSWER ASAP!!
Margarita [4]

Morphology

Explanation:

The shape and pigment of the hairs are the morphological elements of the two hair strands.

Morphology deals with the study of the form and structure of organisms, plants and their components.

  • The shape, size, color, textures, orientation are all morphological elements that can be used to draw biological comparison between things.
  • It also entails the relationship between the structures with each other.
  • Morphology is an expression of the genotypic make up of an organism.

Learn more:

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2 years ago
What elements are highlighted:<br> a. Nonmetals<br> b. Metals<br> C. Metalloids
Advocard [28]
Non metals
(It’s both halogens and noble gases ) the other ones which are white(not highlighted) are alkali metals, alkaline earth metals, and transition metals :3
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3 years ago
The purpose of warfare in our world
Fudgin [204]

Answer

We are currently working on a dataset of war and large-scale violent events over the long run. If you want to contribute to this research please get in touch.

Explanation:

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3 years ago
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An analytical chemist is titrating of a solution of propionic acid with a solution of 224.9 ml of a 0.6100M solution of propioni
Svetllana [295]

<u>Answer:</u> The pH of acid solution is 4.58

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}    .....(1)

  • <u>For KOH:</u>

Molarity of KOH solution = 1.1000 M

Volume of solution = 41.04 mL

Putting values in equation 1, we get:

1.1000M=\frac{\text{Moles of KOH}\times 1000}{41.04}\\\\\text{Moles of KOH}=\frac{1.1000\times 41.04}{1000}=0.04514mol

  • <u>For propanoic acid:</u>

Molarity of propanoic acid solution = 0.6100 M

Volume of solution = 224.9 mL

Putting values in equation 1, we get:

0.6100M=\frac{\text{Moles of propanoic acid}\times 1000}{224.9}\\\\\text{Moles of propanoic acid}=\frac{0.6100\times 224.9}{1000}=0.1372mol

The chemical reaction for propanoic acid and KOH follows the equation:

                 C_2H_5COOH+KOH\rightarrow C_2H_5COOK+H_2O

<u>Initial:</u>          0.1372         0.04514  

<u>Final:</u>           0.09206          -                0.04514

Total volume of solution = [224.9 + 41.04] mL = 265.94 mL = 0.26594 L     (Conversion factor:  1 L = 1000 mL)

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[\text{salt}]}{[acid]})

pH=pK_a+\log(\frac{[C_2H_5COOK]}{[C_2H_5COOH]})

We are given:  

pK_a = negative logarithm of acid dissociation constant of propanoic acid = 4.89

[C_2H_5COOK]=\frac{0.04514}{0.26594}

[C_2H_5COOH]=\frac{0.09206}{0.26594}

pH = ?  

Putting values in above equation, we get:

pH=4.89+\log(\frac{(0.04514/0.26594)}{(0.09206/0.26594)})\\\\pH=4.58

Hence, the pH of acid solution is 4.58

7 0
3 years ago
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