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KonstantinChe [14]
2 years ago
12

Which phrase describes the decay modes and the half-lives of K-37 and K-42?

Chemistry
2 answers:
True [87]2 years ago
7 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Among the choices the phrase describes the decay modes and the half-lives of K-37 and K-42 is different decay modes and different half-lives 
andrew11 [14]2 years ago
6 0

Answer: (3) different decay modes and different half-lives

Explanation: Potassium-37 and Potassium-42 have the same number of protons  but different numbers of neutrons i.e. they have same atomic number but different mass number. They are isotopes. Thus K-37 and K-42 have different decay modes

K-37 is positron decay and K-42 is beta decay.

_{19}^{37}{\textrm {Kr}}\rightarrow _{18}^{37}{\textrm {Ar}}+_{+1}^0{\textrm {e}}

_{19}^{42}{\textrm {Kr}}\rightarrow _{20}^{42}{\textrm {Ca}}+_{-1}^0{\textrm {e}}


K-37 has a half life of 1.23 seconds and K-42 has a half life of 12.4 hrs.

Thus they have different decay modes and different half lives.

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The potential difference is considered as the change in terms of voltage or Del V. It is measured in terms of voltage so that statement got the name voltage change between point A & B is 1. It means that I joule of work is carried out for moving the 1 coulomb of charge from the point A to B.

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2 years ago
Even though lead is toxic, lead compounds were used in ancient times as white pigments in cosmetics. What is the percentage of l
Gekata [30.6K]

<u>Answer:</u> The mass percent of lead in lead (IV) carbonate is 63.32 %

<u>Explanation:</u>

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To calculate the mass percentage of lead in lead (IV) carbonate, we use the equation:

\text{Mass percent of lead}=\frac{\text{Mass of lead}}{\text{Mass of lead (IV) carbonate}}\times 100

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Mass of lead (IV) carbonate = [(1 × 207.2) + (2 × 12) + (6 × 16)] = 327.2 g

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4 0
2 years ago
How many moles of NaCl are created as a result of decomposing 12 grams of NaClO3? (molar mass of Na=23, Cl=35, O=16)
Harman [31]

Answer: 0.113 moles of NaCl are created as a result of decomposing 12 grams of NaClO_3.

Explanation:

To calculate the moles :

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8 0
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Ainat [17]

Answer:

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