1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
KonstantinChe [14]
3 years ago
12

Which phrase describes the decay modes and the half-lives of K-37 and K-42?

Chemistry
2 answers:
True [87]3 years ago
7 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Among the choices the phrase describes the decay modes and the half-lives of K-37 and K-42 is different decay modes and different half-lives 
andrew11 [14]3 years ago
6 0

Answer: (3) different decay modes and different half-lives

Explanation: Potassium-37 and Potassium-42 have the same number of protons  but different numbers of neutrons i.e. they have same atomic number but different mass number. They are isotopes. Thus K-37 and K-42 have different decay modes

K-37 is positron decay and K-42 is beta decay.

_{19}^{37}{\textrm {Kr}}\rightarrow _{18}^{37}{\textrm {Ar}}+_{+1}^0{\textrm {e}}

_{19}^{42}{\textrm {Kr}}\rightarrow _{20}^{42}{\textrm {Ca}}+_{-1}^0{\textrm {e}}


K-37 has a half life of 1.23 seconds and K-42 has a half life of 12.4 hrs.

Thus they have different decay modes and different half lives.

You might be interested in
Which of the following might decrease the amount of water available in an ecosystem?Spilling oil
dolphi86 [110]

Answer:

constructing a dam

Explanation:

dams separate water

3 0
3 years ago
A chemist makes 940. mL of sodium carbonate (Na_2CO_3) working solution by adding distilled water to 200. mL of a 0.171 m stock
Alexxandr [17]

Answer:

The answer is 0.0698 M

Explanation:

The concentration was prepared by a serial dilution method.

The formula for the preparation I M1V1 = M2V2

M1= the concentration of the stock solution = 0.171 M

V1= volume of the stock solution taken = 200 mL

M2 = the concentration produced

V2 = the volume of the solution produced = 940 mL

Substitute these values in the formula

0.171 × 200 = 490 × M2

34.2 = 490 × M2

Make M2 the subject of the formula

M2 = 34.2/490

M2 = 0.069795

M2 = 0.0698 M ( 3 s.f)

The concentration of the Chemist's working solution to 3 significant figures is 0.0698M

6 0
3 years ago
What process does a new substance form
Dennis_Churaev [7]
Chemical changes occur when a substance combines with another to form a new substance, called synthesis or, alternatively, decomposes into two or more different substances. 
8 0
3 years ago
Alguien saber esto? Literal no se este material
Vikki [24]

Answer:

2. 389.15K , 3. 229.15K

Explanation:

K-273.15 = °C

3 0
3 years ago
1.25 is the closest to 1.04 or not I want to answer please. I think it's true, but I want to prove it scientifically, please.
PSYCHO15rus [73]

Answer:

false because if you round both of them

3 0
3 years ago
Other questions:
  • Calculate the molarity of a solution prepared by dissolving 195 g of sodium chloride (NaCl) in enough water to make 2.8 liters o
    10·1 answer
  • Who was the first to state the concept of an atom?
    14·2 answers
  • Mendeleev used his periodic table of elements to
    11·1 answer
  • Which temperature scale would read the highest number for boiling water? A. Kelvin B. Celsius C. Fahrenheit
    6·2 answers
  • What does a chemist do​
    9·1 answer
  • Which of the following is a correct statement about collision theory?
    13·2 answers
  • 2] Calculate the percentage of the element forming sugar glucose C6H1206<br>[C=12, H=1, 0=16]​
    7·1 answer
  • In Philip’s French class, the students are learning how to pronounce closed vowels and open vowels. The students are most likely
    10·2 answers
  • Describe how to test your unknown salt mixture for the presence of<br>Na3PO4.12H2O.​
    5·1 answer
  • Help me please? <br>I need to pass this tomorrow ​
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!