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beks73 [17]
3 years ago
11

In your own words describe what free fall is

Physics
2 answers:
sertanlavr [38]3 years ago
8 0
<h2><em>in your own words describe what free fall is</em></h2>

  • <em>it's </em><em>an </em><em>object </em><em>only </em><em>the </em><em>gravity </em><em>of </em><em>the </em><em>earth</em><em> </em><em>without</em><em> </em><em>any </em><em>force </em><em>of </em><em>acting</em>

<em>hope </em><em>it</em><em> helps</em>

<em>#</em><em>c</em><em>a</em><em>r</em><em>r</em><em>y</em><em> </em><em>on</em><em> learning</em>

nekit [7.7K]3 years ago
6 0

Answer:

u are falling

Explanation:

In Newtonian physics, free fall is any motion of a body where gravity is the only force acting upon it. In the context of general relativity, where gravitation is reduced to a space-time curvature, a body in free fall has no force acting on it.

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g determine what frequency is required of a source powering a 100 uf capacitor a 500 ohm resistor and a s50 mH inductor in serie
polet [3.4K]

Answer: 71.16\ Hz

Explanation:

Given

Capacitance C=100\ \mu F

Resistance R=500\ \Omega

Inductance L=50\ mH

In LCR circuit, current is maximum at resonance frequency i.e.

X_L=X_C\ \text{and}\ \omega_o=\dfrac{1}{\sqrt{LC}}

Insert the values

\Rightarrow \omega_o=\dfrac{1}{\sqrt{50\times 10^{-3}\times 100\times 10^{-6}}}\\\\\Rightarrow \omega_o=\dfrac{1}{\sqrt{5}\times 10^{-3}}\\\\\Rightarrow \omega_o=0.447\times 10^{3}

Also, frequency is given by

\Rightarrow 2\pi f=\omega_o\\\\\Rightarrow f=\frac{\omega_o}{2\pi}

\Rightarrow f=\dfrac{1}{2\pi}\times 0.447\times 10^3\\\\\Rightarrow f=71.16\ Hz

8 0
3 years ago
A busy waitress slides a plate of apple pie along a counter to a hungry customer sitting near the
Ostrovityanka [42]

Answer:

a. 0.5307 sec

b. 0.4458 m

c. =v_x=0.84\ m/s\ ,\ v_y=5.2\ m/s

Explanation:

Horizontal Motion

It describes the dynamics of an object thrown horizontally in free air. The initial horizontal velocity is maintained all the time since no horizontal forces are acting. The initial vertical velocity is zero at launch time, but it grows downwards powered by the acceleration of gravity.  

The object hits the ground at a distance x from the point of launching, after having traveled a vertical distance y_o, taking a time t to complete the travel. The formulas who relate the different magnitudes are

v_x=v_o

The horizontal velocity v_x is the same regardless of the elapsed  time

v_y=gt

x=v_ot

\displaystyle y=y_o-\frac{gt^2}{2}

The plate of apple pie left the counter at a speed  

v_o=0.84\ m/s

The counter is y_o=1.38\ m high.

a.

Knowing that

y_o=1.38\ m

We use this formula to compute t

\displaystyle y=y_o-\frac{gt^2}{2}

At the moment when the plate hits the floor y=0

\displaystyle 0=y_o-\frac{gt^2}{2}

\displaystyle y_o=\frac{gt^2}{2}

Solving for t

\displaystyle t=\sqrt{\frac{2y_o}{g}}

\displaystyle t=\sqrt{\frac{2(1.38)}{9.8}}

t=0.5307\ sec

b.

x=(0.84)(0.5307)

x=0.4458\ m

c.

v_x=0.84\ m/s

v_y=(9.8)(0.5307)

v_y=5.2\ m/s

3 0
4 years ago
A laser emits light at power 6.20 mW and wavelength 633 nm. The laser beam is focused (narrowed) until its diameter matches the
Ipatiy [6.2K]

Answer:

a) S = 1.69 10⁹ W/m², b)  P = 5.63 Pa , c) F = 20.6 10⁻¹² N

Explanation:

a) The intensity defined as the energy per unit area

    S = U / A

Area of ​​a circle is

    W = 6.2 mw = 6.2 10-3 W

    R = 1080 nm = 1080 10⁻⁹ m  = 1.080 10⁻⁶ m

   A = π R2

   A = π (1,080 10⁻⁶)²

   A = 3.66 10 -12 m²

   S = 6.2 10-3 / 3.66 10-12

   S = 1.69 10⁹ W / m²

b) The radiation pressure

   P = 1 / c (dU / dt) / A

   S = (dU / dt) / A

   

   P = S / c

   P = 1.69 10 9 / 3. 108

   P = 5.63 Pa

c) the definition of pressure is force over area

   P = F / A

   F = P A

   F = 5.63 3.66 10⁻¹²

   F = 20.6 10⁻¹² N

d) for this we use Newton's second law

   F = ma

   a = F / m

8 0
3 years ago
A.) If its booster rockets accelerate the space shuttle at 15m/s2, how high will it be one minute after launch?
poizon [28]

Answer:

27,000 m

450 m/s

Explanation:

Assuming the initial velocity is 0 m/s:

v₀ = 0 m/s

a = 15 m/s²

t = 60 s

A) Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (60 s) + ½ (15 m/s²) (60 s)²

Δy = 27,000 m

B) Find: v_avg

v_avg = Δy / t

v_avg = 27,000 m / 60 s

v_avg = 450 m/s

5 0
3 years ago
If we go on the top of the Mountain we will our weight increase or decrease?​
erma4kov [3.2K]

Answer:

increase

Explanation:

guesshejwoowsnnsnakalalapqjhdjd

7 0
3 years ago
Read 2 more answers
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