3 years ago

If the molar heat of vaporization for water is 40.7 kJ/mol. What is the molar heat of condensation? HELP ME PLEASE!!!

Chemistry

1 answer:

Yanka [14]3 years ago

5 0

Answer:

not sure hope you have a good day

You might be interested in

12. What is the main cause of movement of water in oceans?

Artemon [7]

Answer:

i think it's convection

3 0

3 years ago

Determine the mass density, specific volume and specific weight of a liquid whose

irakobra [83]

the volume is 63 i hope it is

5 0

3 years ago

The Paris Agreement intends to direct money toward limiting climate change and lowering greenhouse gas levels. Which groups are

yan [13]

I think the answer it’s e

7 0

4 years ago

Read 2 more answers

Solid cadmium sulfide reacts with an aqueous solution of sulfuric acid . Express your answer as a balanced chemical equation. Id

max2010maxim [7]

Explanation:

When solid cadmium sulfide reacts with an aqueous solution of sulfuric acid then the reaction will be as follows.

$CdS(s) + H_{2}SO_{4}(aq) \rightarrow CdSO_{4}(aq) + H_{2}S(g)$

Hence, ionic equation for this reaction is as follows.

$CdS(s) + 2H^{+}(aq) + SO^{2-}_{4}(aq) \rightarrow Cd^{2+}(aq) + SO^{2-}_{4}(aq) + H_{2}S(g)$

Therefore, net ionic equation for this reaction is as follows.

$CdS(s) + 2H^{+}(aq) \rightarrow Cd^{2+}(aq) + H_{2}S(g)$

8 0

3 years ago

fish tank initially contains 35 liters of pure water. Brine of constant, but unknown, concentration of salt is flowing in at 5 l

weeeeeb [17]

Answer:

Therefore, the rate of change in the amount of salt is $\frac{dx}{dt} =( 5c}{ - \frac{x }{20})$

$\frac{grams }{min}$

Explanation:

Given:

Initial volume of water $V = 35$ lit

Flowing rate = 5 $\frac{Lit}{min}$

The rate of change in the amount of salt is given by,

$\frac{dx}{dt} =$ ( Rate of salt enters tank - rate of sat leaves tank )

Since tank is initially filled with water so we write that,

$x(0) = 0$

Let amount of salt in the solution is $c$ ,

$\frac{dx}{dt} = \frac{5c}{1 } - \frac{x(t) \times 5}{100}$

$\frac{dx}{dt} =( 5c}{ - \frac{x }{20})$ $\frac{grams}{min}$

Therefore, the rate of change in the amount of salt is $\frac{dx}{dt} =( 5c}{ - \frac{x }{20})$

$\frac{grams }{min}$

7 0

3 years ago