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Nutka1998 [239]
3 years ago
9

Example of a homoatomic and heteroatomic molecule

Chemistry
1 answer:
il63 [147K]3 years ago
3 0

Answer:

Some examples of homoatomic molecules are hydrogen gas, and oxygen gas and some examples of heteroatomic molecules are water, methane

Explanation:

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Element X is in group 2, and element Y is in group 7, of the periodic table. which ions will be present in the compound formed w
12345 [234]

Answer:

Element X has valency 2 while Y Valency 2, element Y has high tendency of gaining electrons for its stability thus the compound formed will be B

elements X is positively charged while Y will be negatively charged

8 0
2 years ago
According to the kinetic molecular theory of gases, molecules of an ideal gas
Elan Coil [88]
Molecules of an ideal gas is composed of a large number of identical molecules moving in random directions, separated by distances that are large compared with their size.
7 0
3 years ago
The d-metals iron, copper, and manganese form cations with different oxidation states. For this reason, they are found in many o
choli [55]

Answer:

They have electrons in their 3d- and 4s-orbital for bond formation.

Explanation:

d- metals or transition metal are metal which form ion with partially filled d-orbital. Examples are iron and manganese.

The metals have 2 electrons in their 4s orbital. If only this is used for bonding, they will form compounds where they have oxidation State of +2 as seen in MnO.

If two 4s and one of 3d electrons are used, oxidation state of +3 is formed as seen in FeCl3.

If two 2s electron I used with two 3d electrons, compound with oxidation state of +4 is formed as seen in MnO2

4 0
3 years ago
Read 2 more answers
Calculate the standard potential for the following galvanic cell: Fe(s) | Fe2+(aq) || Ag+(aq) | Ag(s) which has the overall bala
Nataly [62]

Answer:

E° = 1.24 V

Explanation:

Let's consider the following galvanic cell: Fe(s) | Fe²⁺(aq) || Ag⁺(aq) | Ag(s)

According to this notation, Fe is in the anode (where oxidation occurs) and Ag is in the cathode (where reduction occurs). The corresponding half-reactions are:

Anode: Fe(s) ⇒ Fe²⁺(aq) + 2 e⁻

Cathode: Ag⁺(aq) + 1 e⁻ ⇒ Ag(s)

The standard cell potential (E°) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E° = E°red, cat - E°red, an

E° = 0.80 V - (-0.44 V) = 1.24 V

6 0
3 years ago
What is the weight in grams of 3.36 × 10Ƴ molecules of copper sulfate (CuSOÁ)?
spin [16.1K]
Molar mass ( CuSO₄) = 159.609 g/mol

159.609 g ----------------- 6.02 x 10²³ molecules
         ? g ------------------ 3.36 x 10²³ molecules

mass = ( 3.36 x10²³) x 159.609 / 6.02 x 10²³

mass = 5.36 x 10²⁴ / 6.02 x 10²³

mass = 8.90 g 

hope this helps!
6 0
3 years ago
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