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Nutka1998 [239]
3 years ago
9

Example of a homoatomic and heteroatomic molecule

Chemistry
1 answer:
il63 [147K]3 years ago
3 0

Answer:

Some examples of homoatomic molecules are hydrogen gas, and oxygen gas and some examples of heteroatomic molecules are water, methane

Explanation:

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Which feature of a balanced chemical equation demonstrates the law of
Scrat [10]

Answer:

Option D

Explanation:

it has the same types of atoms on both sides of the reaction

8 0
3 years ago
Read 2 more answers
7. The molar mass of carbon is 12.0 g/mol, of hydrogen is 1.0 g/mol, and of oxygen is 16.0 g/mol.
Ivan

Answer:

2 x 12.0g/mol + 1 x6 +  16.0 g/mol

Explanation:

molecular formula = C₂H₆O           ( carbon= 12g/mol  H= 1g     O=16)

                              =   2 x 12 + 6 x 1 + 16

                             =  46 g    Molecular mass                                

                             

3 0
3 years ago
Hydrogen sulfide decomposes according to the following reaction: 2H2S(g) ⇋ 2H2(g) + S2(g) Kc=9.30x10-8 at 700.°C.If 0.45 mol of
Natalija [7]

Answer:

[H₂] = 1.61x10⁻³ M

Explanation:

2H₂S(g) ⇋ 2H₂(g) + S₂(g)

Kc = 9.30x10⁻⁸ = \frac{[H_{2}]^2[S_{2}]}{[H_{2}S]^2}

First we <u>calculate the initial concentration</u>:

0.45 molH₂S / 3.0L = 0.15 M

The concentrations at equilibrium would be:

[H₂S] = 0.15 - 2x

[H₂] = 2x

[S₂] = x

We <u>put the data in the Kc expression and solve for x</u>:

\frac{(2x^2) * x}{(0.15-2x)^2}=9.30x10^{-8}

\frac{4x^3}{0.0225-4x^2}=9.30*10^{-8}

We make a simplification because x<<< 0.0225:

\frac{4x^3}{0.0225} =9.30*10^{-8}

x = 8.058x10⁻⁴

[H₂] = 2*x = 1.61x10⁻³ M

5 0
3 years ago
Read 2 more answers
‼️ i really need help. if anyone can do 10 pages of a grade 11 chemistry packet (multiple choice) let me know. i can pay money
Alja [10]

Answer:

mmmmmmmmmmmmmmmmmm

Explanation:

6 0
3 years ago
A car is moving at a velocity of 75 m/s and comes to a complete stop
Mice21 [21]

Answer:

The acceleration of the car is  -5m/s²

Explanation:

Given parameters:

Initial velocity  = 75m/s

Final velocity  = 0m/s

Time  = 15s

Unknown:

Acceleration of the car = ?

Solution:

Acceleration is the rate of change of velocity with time;

Mathematically;

      Acceleration = \frac{Final velocity - Initial velocity }{time}

Insert parameters and solve,

   Acceleration  = \frac{ 0- 75}{15}   = -5m/s²

The acceleration of the car is  -5m/s²

3 0
3 years ago
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