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erastova [34]
3 years ago
5

The total mass of the products in a chemical reaction is _______

Physics
1 answer:
never [62]3 years ago
5 0

total mass of the reactants

Explanation:

In a chemical reaction, the total mass of products is the same as the total mass of reactant.

For chemical equations to have meaning, they must be balanced. A balanced equation is one that obeys the law of conservation of matter. This law states that "matter is neither created nor destroyed in the course of a chemical reaction".

  • The law implies that that the total mass of the reacting substances is exactly equal to the total mass of the products. .
  • Therefore, all other kinds of atoms are conserved.

learn more:

conservation of matter brainly.com/question/2190120

#learnwithBrainly

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A 60​-m-long chain hangs vertically from a cylinder attached to a winch. Assume there is no friction in the system and that the
Mariulka [41]

Answer:

part (a). 176580 J

part (b). 197381 J

Explanation:

Given,

  • Density of the chain = \rho\ =\ 10\ kg/m.
  • Length of the chain = L = 60 m
  • Acceleration due to gravity = g = 9.81 m/s^2

part (a)

Let dy be the small element of the chain at a distance of 'y' from the ground.

mass of the small element of the chain = \rho dy

Work done due to the small element,

dw\ =\ \rho g (60\ -\ y)dy\\

Total work done to wind the entire chain = w

w\ =\ \displaystyle\int_{0}^{L} \rho g(60\ -\ y)dy\\\Rightarrow  w\ =\ \rho g\left |(60y\ -\ \dfrac{y^2}{2})\ \right |_{0}^{60}\\\Rightarrow w\ =\ 10\times 9.81\times (60\times 60\ -\ \dfrac{60^2}{2})\\\Rightarrow w\ =\ 176580\ J

part (b)

  • mass of the block connected to the chain = m = 35 kg

Total work done to wind the chain = work done due to the chain + work done due to the mass

\therefore W\ =\ w\ +\ mgL\\\Rightarrow W\ =\ 176580\ +\ 35\times 9.81\times 60\\\Rightarrow W\ =\ 176580\ +\ 20601\\\Rightarrow W\ =\ 197381\ J

4 0
2 years ago
How do we know that water dissolves glue?
malfutka [58]
By testing it out. Try it.
7 0
2 years ago
List at least five examples of minerals and their common uses.
GarryVolchara [31]

Answer:

Beryllium

Beryllium is an alkaline metallic element that is highly toxic. It is known for its sugary sweet taste and some of its common uses are in X-rays and fluorescent lights.

Beryllium : A very thorough and technical site about this mineral.

Chromite

Chromite is the ore of chromium and is a very hard metal, and diamond is the only thing harder. This hardness is what allows a chrome finish to take a high polish.

Chromite : This site talks about its history and characteristics.

Cobalt

Cobalt is famous for the incredible blue color it imparts to glass and pigment. It has been found in meteorites and is used in invisible ink. It is a brittle metal and resembles iron.

Cobalt : This site has photos, video, charts and physical and atomic descriptions.

Columbite-tantalite

Columbite-tantalite group is a mineral used widely in technology. Electronics, automotive systems and health products like the pacemaker need this mineral to operate. It is mined in Africa and has earned the name of Coltan over the last few years.

Columbite-tantalite : Information about its role in the world under the name 'Coltan'.

Copper

Copper is a common metal throughout the world. It is used for currency, jewelry, plumbing and to conduct electricity. It is a soft, orange-red metal.

Copper : This site talks about its properties, uses and makeup.

Explanation:

Hope that helps :)

4 0
3 years ago
What is the amount of the force accelerate a 20kg object at a rate of 5m/s
Anni [7]

Answer:

100 N is the answer of the question

6 0
2 years ago
A 1.2 kg block of wood hangs motionless from strings. A 50 gram bullet, traveling horzontally, strikes the block and becomes emb
Firdavs [7]

Answer:

speed of the bullet before it hit the block is 200 m/s

Explanation:

given data

mass of block m1 = 1.2 kg

mass of bullet m2 = 50 gram = 0.05 kg

combine speed V= 8.0 m/s

to find out

speed of the bullet before it hit the block

solution

we will apply here conservation of momentum that is

m1 × v1 + m2 × v2 = M × V    .............1

here m1 is mass of block and m2 is mass of bullet and v1 is initial speed of block i.e 0 and v2 is initial speed of bullet and M is combine mass of block and bullet and V is combine speed of block and bullet

put all value in equation 1

m1 × v1 + m2 × v2 = M × V

1.2 × 0 + 0.05 × v2 = ( 1.2 + 0.05 ) × 8

solve it we get

v2 = 200 m/s

so speed of the bullet before it hit the block is 200 m/s

8 0
3 years ago
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