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STatiana [176]
3 years ago
6

A parallel-plate capacitor is formed from two 9.1 cm-diameter electrodes spaced 1.3 mm apart. The electric field strength inside

the capacitor is 5.0×106N/C.
What is the charge (in nC) on each electrode?

Physics
1 answer:
vitfil [10]3 years ago
6 0

Answer:

2.87nC

Explanation:

See attached file

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A compressor receives air at 290 K, 100 kPa and a shaft work of 5.5 kW from a gasoline engine. It is to deliver a mass flow rate
Sladkaya [172]

Answer:

P_2=4091\ KPa

Explanation:

Given that

T₁ = 290 K

P₁ = 100 KPa

Power P =5.5 KW

mass flow rate

\dot{m}= 0.01\ kg/s

Lets take the exit temperature = T₂

We know that

P=\dot{m}\ C_p (T_2-T_1)

5.5=0.01\times 1.005(T_2-290})\\T_2=\dfrac{5.5}{0.01\times 1.005}+290\ K\\\\T_2=837.26\ K

If we assume that process inside the compressor is adiabatic then we can say that

\dfrac{T_2}{T_1}=\left(\dfrac{P_2}{P_1}\right)^{0.285}

\dfrac{837.26}{290}=\left(\dfrac{P_2}{100}\right)^{0.285}\\2.88=\left(\dfrac{P_2}{100}\right)^{0.285}\\

2.88^{\frac{1}{0.285}}=\dfrac{P_2}{100}

P_2=40.91\times 100 \ KPa

P_2=4091\ KPa

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Explanation:

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3 years ago
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