Answer:
Yo, you just kind of answered it yourself. The Electron Cloud Model is the informal way of describing an atomic orbital.
Explanation:
The analogy of the cloud of electrons is really describing the groups of electrons orbiting around said atom. Depending on the atom, there will be many or few electrons orbiting around it on all sides which can resemble an all-encompassing cloud.
Answer:
A.The vertical velocity is constantly increasing as the ball falls.
B.The horizontal velocity does not noticeably change as the ball falls.
G.The horizontal velocity does not affect how long it will take the ball to fall to the floor.
H.The velocity vector of the ball changes as it travels through the air.
Explanation:
As the ball is projected horizontally so here the vertical component of the velocity is zero
So the time to reach the ground is given as
so we will have
so this is the same time as the ball is dropped from H height
Since there is no force in horizontal direction so its horizontal velocity will always remain constant while vertical velocity will change at constant rate which is equal to acceleration due to gravity.
So overall the velocity vector will change due to net acceleration g
Answer:
Option D is correct: 170 µW/m²
Explanation:
Given that,
Frequency f = 800kHz
Distance d = 2.7km = 2700m
Electric field Eo = 0.36V/m
Intensity of radio signal
The intensity of radial signal is given as
I = c•εo•Eo²/2
Where c is speed of light
c = 3×10^8m/s
εo = 8.85 × 10^-12 C²/Nm²
I = 3×10^8 × 8.85×10^-12 × 0.36²/2
I = 1.72 × 10^-4W/m²
I = 172 × 10^-6 W/m²
I = 172 µW/m²
Then, the intensity of the radio wave at that point is approximately 170 µW/m²
Answer:
True
Explanation:
An electric field is a region around a charged particle or object within which a force would be exerted on other charged particles or objects.
Answer:
Explanation:
In Coulomb's law the force between the charged objects depends on the distance between them which is inversely proportional to the force and the charge of the objects which is directly proportional to the force with proportional constant K.
Because q₂ is near to another charged object q₁, then, it will experience an electric force exerted by q₁.
F₁₂ = K |q₁| |q₂|/r²
= K (|-e|) (|+e|)/r²
= (9.0 x 10⁹ N.m²/C²) x (1.6 x 10⁻¹⁹ C) x (1.6 x 10⁻¹⁹ C)/ (0.80 x 10⁻⁹)²
= 3.6 x 10⁻¹⁰ N
Force F₁₂ = F₂₁
Because the two charged objects have different signs , then, the force between them will be an attractive force.