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3 years ago

10

What is the element name for 2,5

1 answer:

Nataly_w [17]3 years ago

4 0

Answer:

I think it's vanadium

Explanation:

Hope this helps

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victus00 [196]

Explanation:

The given data is as follows.

q = 69.0 kJ = 69000 J (as 1 kJ = 1000 J),

mass (m) = 8.10 kg = 8100 g (as 1 kg = 1000 g)

$T_{i} = 33.9^{o}C$ = (33.9 + 273) K = 306.9 K

C = 4.18 J/gK

As we know that the relation between heat and change in temperature is as follows.

q = $m \times C \times \Delta T$

Putting the values into the above formula to calculate the final temperature as follows.

q = $m \times C \times \Delta T$

69000 J = $8100 g \times 4.18 J/g K \times (T_{f} - 306.9 K)$

69000 J = $33858 \times (T_{f} - 306.9 K)$

$(T_{f} - 306.9 K)$ = 2.037 K

$T_{f}$ = (2.037 + 306.9) K

= 308.9 K

or, = 309 K (approx)

Thus, we can conclude that the new temperature of the water bath is 309 K.

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