How many grams of water will be produced if there are 3.5 miles of oxygen?

Arrange the following aqueous solutions in order of decreasing freezing point: 0.10 m Na3PO4, 0.35 m NaCl, 0.20 m MgCl2, 0.15 m

GarryVolchara [31]

Answer: 0.35 m $NaCl$ > 0.20 m $MgCl_2$ >0.10 m $Na3PO_4$ > 0.15 m $CH_3COOH$ > 0.15 m $C_6H_{12}O_6$

Explanation:

Depression in freezing point:

$T_f^0-T_f=i\times k_b\times m$

where,

$T_f$ = freezing point of solution

$T^o_f$ = freezing point of solvent

$k_f$ = freezing point constant

m = molality

1. For 0.10 m $Na3PO_4$

$Na_3PO_4\rightarrow 3Na^++PO_4^{3-}$

, i= 4 as it is a electrolyte and dissociate to give 4 ions. and concentration of ions will be $4\times 0.10=0.40$

2. For 0.35 m $NaCl$

$NaCl\rightarrow Na^++Cl^-$

, i= 2 as it is a electrolyte and dissociate to give 2 ions. and concentration of ions will be $2\times 0.35=0.70$

3. For 0.20 m $MgCl_2$

$MgCl_2\rightarrow Mg^{2+}+2Cl^-$

, i= 3 as it is a electrolyte and dissociate to give 3 ions. and concentration of ions will be $3\times 0.20=0.60$

4. For 0.15 m $C_6H_{12}O_6$

, i= 1 as it is a non electrolyte and does not dissociate to give ions.

5. For 0.15 m $CH_3COOH$

$CH_3COOH\rightarrow CH_3COO^-+H^+$

, i= 2 as it is a electrolyte and dissociate to give 2 ions and thus have $2\times 0.15=0.30$

As concentration is highest for 0.35 m $NaCl$ , freezing point depression will be highest and thus has lowest freezing point. As concentration is lowest for 0.15 m $C_6H_{12}O_6$ , freezing point depression will be lowest and thus has highest freezing point

8 0

3 years ago

Practice Problems Exercise 8.6 Classify each of the following reactions in as many ways as possible.4N H3 (g) 5 O2 (g) n 4NO(g)

nikklg [1K]

Explanation :

(a) $4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g)$

This reaction is combustion reaction in which an oxygen react with a molecule to give its corresponding oxides ans water molecule.

(b) $S_8(s)+8O_2(g)\rightarrow 8SO_2(g)$

This reaction is a redox reaction or oxidation-reduction reaction in which sulfur get oxidized and oxygen get reduced.

(c) $2Al(s)+3Cl_2(g)\rightarrow 2AlCl_3(s)$

This reaction is a combination reaction in which the two reactants molecule combine to form a large molecule or product.

(d) $2AlN\rightarrow 2Al(s)+N_2(g)$

This reaction is a decomposition reaction in which a large molecule or reactant decomposes to give two or more molecule or products.

(e) $BaCl_2(aq)+Na_2SO_4(aq)\rightarrow BaSO_4(s)+2NaCl(aq)$

This reaction is a double displacement reaction in which the cation of two reactants molecule exchange their places to give two different products.

(f) $2Cs(s)+Br_2(l)\rightarrow 2CsBr(s)$

This reaction is a combination reaction in which the two reactants combine to form a large molecule or product.

(g) $KOH(aq)+HCl(aq)\rightarrow H_2O(l)+KCl(aq)$

This reaction is a double displacement reaction in which the cation of two reactants molecule exchange their places to give two different products.

(h) $2C_2H_2(g)+5O_2(g)\rightarrow 4CO_2(g)+2H_2O(l)$

This reaction is combustion reaction in which a hydrocarbon react with an oxygen to give carbon dioxide and water as a products.

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What is the purpose of the prefixes in the metric system?

Helen [10]

Prefixes are used in the metric system to indicate smaller or larger measurements

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Which statement describes the change that occurs during the reaction of tin with lead(II) nitrate? A. Tin atoms give electrons t

timama [110]

Answer is: D. Tin atoms give electrons to lead(II) ions and are oxidized to tin(II) ions.
Chemical reaction: Sn⁰ + Pb²⁺ → Sn²⁺ + Pb.
Tin atom (oxidation number 0) give two electrons to led ions, oxidation number of tin is greater now (oxidation number +2).
Oxidation is loss of electrons.

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3 years ago

NEED HELP NOW which materials allow heat to pass through them easily?

Rashid [163]

The materials which allow heat to pass through them easily are conductors of heat. For examples,aluminum, iron, and copper.

Hope this helps! ;)

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3 years ago

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