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Paul [167]
3 years ago
8

?!?!??!! Plz helllppp

Mathematics
1 answer:
siniylev [52]3 years ago
8 0
What do you need help with ?
You might be interested in
Greg has enough framing to enclose a rectangular photograph with a perimeter of 160 centimeters. If the width of his photograph
kotegsom [21]

Answer:

32cm

Step-by-step explanation:

Let the width be w. Now we know that the width is 16cm less than the length, this means that the length will thus have a total length of w + 16

Now, we know that the perimeter of a rectangle is 2(l + b)

This means 2(w + w + 16) = 160

4w + 32 = 160

4w = 128

w = 128/4 = 32cm

8 0
4 years ago
What is the distance from Mto N?
aivan3 [116]

9514 1404 393

Answer:

  C.  10 units

Step-by-step explanation:

The distance MN can be found using the distance formula.

  d = √((x2 -x1)² +(y2 -y1)²)

  d = √((2 -(-4))² +(3 -(-5))²) = √(6² +8²) = √100 = 10

The distance from M to N is 10 units.

5 0
3 years ago
Please actually show ur work on how u got the answer thank u
serg [7]

Answer:

C

Step-by-step explanation:

I substituted the x value with the different options. I kept doing that until the equation made sense.

4 0
3 years ago
Read 2 more answers
Evaluate the definite integral. <br> 1 x4(1 + 2x5)5 dx.
Nata [24]

Answer:

Step-by-step explanation:

Given the definite integral \int\limits {\dfrac{x^4}{(1-2x^5)^5} } \, dx, we to evaluate it. Using integration by substitution method.

Let u = 1-2x⁵ ...1

du/dx = -10x⁴

dx = du/-10x⁴.... 2

Substitute equation 1 and 2 into the integral function and evaluate the resulting integral as shown;

= \int\limits {\dfrac{x^4}{u^5} } \, \dfrac{du}{-10x^4}

= \dfrac{-1}{10} \int\limits {\dfrac{du}{u^5} }  \\\\= \dfrac{-1}{10} \int\limits {{u^{-5}du }  \\= \dfrac{-1}{10} [{\frac{u^{-5+1}}{-5+1}]  \\\\= \dfrac{-1}{10} ({\frac{u^{-4}}{-4})\\\\

= \dfrac{u^{-4}}{40} \\\\\\= \dfrac{1}{40u^4} +C

substitute u = 1-2x⁵ into the result

= \dfrac{1}{40(1-2x^5)^4} +C

Hence\int\limits {\dfrac{x^4}{(1-2x^5)^5} } \, dx = \dfrac{1}{40(1-2x^5)^4} +C

5 0
3 years ago
Criminal investigators use biometric matching for fingerprint recognition, facial recognition, and iris recognition. When matchi
Daniel [21]

Answer:

Type I error.

Step-by-step explanation:

Let's remember the definition of Type I error and Type II error:

A type I error is the rejection of a true null hypothesis, this means that we would get a "false positive" with this error.

A type II error is the non rejection of a not true null hypothesis, this error would give us a "false negative".

In this problem, we are told that the mean match score to identify a suspect is 80. However, the test shows that the mean match score is more than 80 when the person doesn't have a fingerprint match (and therefore the person would not be a suspect). Therefore, this person would appear as a suspect when he/she really isn't one. This means that the test is giving a "false positive". Thus, this is a type I error.

6 0
3 years ago
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