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3 years ago

What is the difference between speech recognition and speech synthesis?

Engineering

2 answers:

andrew-mc [135]3 years ago

4 0

Answer:

peech synthesis is being used in programs where oral communication is the only means by which information can be received, while speech recognition is facilitating commu- nication between humans and computers, whereby the acoustic voice signals changes in the sequence of words making up a written text.

Explanation:

taurus [48]3 years ago

4 0

Answer:

Speech synthesis is being used in programs where oral communication is the only means by which information can be received, while speech recognition is facilitating commu- nication between humans and computers, whereby the acoustic voice signals changes in the sequence of words making up a written text.

Explanation:

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A steel cylindrical pressure vessel has an inside diameter of 2m and a wall thickness of 2cm. If the steel has a yield stress Y

Feliz [49]

Answer:

The pressure that will cause yielding in the tank in the longitudinal direction is 1.7 Mpa

Explanation:

We are dealing with a thin-walled pressure vessel here.

the formula for calculating the hoops stress of this pressure vessel is $\sigma =P d/4t$

$\sigma Y =$ longitudinal yield stress = $425 \times 10^{6} Pa$

Thickness = 2/1000 =0.002m

Outside diameter = inside siameter + thickness = 2m + 0.002m= 2.002m

Dm = Mean diameter = Outside diameter - thickness = 2.002 - 0.002 = 2m

$P= 425 \times 10^{6} \times 4 \times 0.002 /2=1.7 Mpa$

4 0

3 years ago

What is the magnitude of the maximum stress that exist at the tip of an internal crack having a radius of curvature of 1.9 x 10-

Hitman42 [59]

Answer:

2800 [MPa]

Explanation:

In fracture mechanics, whenever a crack has the shape of a hole, and the stress is perpendicular to the orientation of such, we can use a simple formula to calculate the maximum stress at the crack tip

$\sigma_{m} = 2 \sigma_{p} (\frac{l_{c}}{r_{c}})^{0.5}$

Where $\sigma_{m}$ is the magnitude of he maximum stress at the tip of the crack, $\sigma_{p}$ is the magnitude of the tensile stress, $l_{c}$ is $1/2$ the length of the internal crack, and $r_{c}$ is the radius of curvature of the crack.

We have:

$r_{c}=1.9*10^{-4} [mm]$

$l_{c}=3.8*10^{-2} [mm]$

$\sigma_{c}=140 [MPa]$

We replace:

$\sigma_{m} = 2*(140 [MPa])*(\frac{\frac{3.8*10^{-2} [mm]}{2}}{1.9*10^{-4} [mm]})^{0.5}$

We get:

$\sigma_{m} = 2*(140 [MPa])*(\frac{\frac{3.8*10^{-2} [mm]}{2}}{1.9*10^{-4} [mm]})^{0.5}=2800 [MPa]$

5 0

3 years ago

The temperature in a pressure cooker is 130 degree C while the water is boiling. Determine the pressure inside the cooker.

emmasim [6.3K]

Answer:

The pressure inside the cooker is 1.0804 atm.

Explanation:

Boiling occurs when the vapor pressure becomes equal to atmospheric pressure.

For water, At standard conditions (Pressure = 1 atm) boiling occurs at 373.15 K.

So, Standard conditions:

T₁ = 373.15 K

P₁ = 1 atm

Given ,

The water boils at Temperature = 130 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So, the temperature, T₂ = (130 + 273.15) K = 403.15 K

To find pressure inside the cooker (P₂) :

Applying Amontons's Law as:

$\frac {P_1}{T_1}=\frac {P_2}{T_2}$

So,

$P_2=\frac {P_1}{T_1} \times {T_2}$

$P_2=\frac {1 atm}{373.15 K} \times {403.15 K}$

$P_2=1.0804 atm$

Thus, The pressure inside the cooker is 1.0804 atm.

6 0

3 years ago

"Vehicles begin to arrive at a parking lot at 6:00 A.M. at a rate of eight per minute. Due to an accident on the access highway,

marin [14]

Answer:

The solution and explanation is attached.

Explanation:

8 0

3 years ago

What is the basic definition of design?

torisob [31]

A design is a plan or specification for the construction of an object or system or for the implementation of an activity or process, or the result of that plan or specification in the form of a prototype, product or process. The verb to design expresses the process of developing a design.

8 0

4 years ago