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3 years ago

What is the difference between speech recognition and speech synthesis?

Engineering

2 answers:

andrew-mc [135]3 years ago

4 0

Answer:

peech synthesis is being used in programs where oral communication is the only means by which information can be received, while speech recognition is facilitating commu- nication between humans and computers, whereby the acoustic voice signals changes in the sequence of words making up a written text.

Explanation:

taurus [48]3 years ago

4 0

Answer:

Speech synthesis is being used in programs where oral communication is the only means by which information can be received, while speech recognition is facilitating commu- nication between humans and computers, whereby the acoustic voice signals changes in the sequence of words making up a written text.

Explanation:

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How many coordinates are required for a 3-dimensional force?

Burka [1]

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4 0

3 years ago

The rate of flow through an ideal clarifier is 8000m3 /d, the detention time is 1h and the depth is 3m. If a full-length movable

Fittoniya [83]

Answer:

a) 35%

b) yes it can be improved by moving the tray near the top

Tray should be located ( 1 to 2 meters below surface )

max removal efficiency ≈ 70%

c) The maximum removal will drop as the particle settling velocity = 0.5 m/h

Explanation:

Given data:

flow rate = 8000 m^3/d

Detention time = 1h

depth = 3m

Full length movable horizontal tray : 1m below surface

a) Determine percent removal of particles having a settling velocity of 1m/h

velocity of critical sized particle to be removed = Depth / Detention time

= 3 / 1 = 3m/h

The percent removal of particles having a settling velocity of 1m/h ≈ 35%

b) Determine if the removal efficiency of the clarifier can be improved by moving the tray, the location of the tray and the maximum removal efficiency

The tray should be located near the top of the tray ( i.e. 1 to 2 meters below surface ) because here the removal efficiency above the tray will be 100% but since the tank is quite small hence the

Total Maximum removal efficiency

= percent removal $_{above}$ + percent removal $_{below}$

= ( d $_{a}$ ,v $_{p}$ ) . $\frac{d_{a} }{depth}$ + ( d $_{a}$ ,v $_{p}$ ) . $\frac{depth - d_{a} }{depth}$ = 100

hence max removal efficiency ≈ 70%

c) what is the effect of moving the tray would be if the particle settling velocity were equal to 0.5m/h?

The maximum removal will drop as the particle settling velocity = 0.5 m/h

7 0

3 years ago

Write code (ReverseNames.java) that prompts the user to enter his or her full name, then prints the name in reverse order (i.e.,

yan [13]

Answer:

import java.util.Scanner;

import java.io.*;

public class Main{

public static void main(String []args){

StringBuilder reversedName = new StringBuilder();

StringBuilder subName = new StringBuilder();

Scanner myObj = new Scanner(System.in); // Create a Scanner object

System.out.println("Enter your full name (last name + first name)");

String name = myObj.nextLine(); // Read user input

for (int i = 0; i < name.length(); i++) {

char currentChar = name.charAt(i);

if (currentChar != ' ') {

subName.append(currentChar);

} else {

reversedName.insert(0, currentChar + subName.toString());

subName.setLength(0);

}

String Resul = reversedName.insert(0, subName.toString()).toString();

System.out.println("Reverse full name: " + Resul);

}

Explanation:

To solve the problem we used StringBuilder, that allow us to build a string letter by letter, we are using two, one to store temporary information (subName) and the other to store the surname plus name (reversedName). After defining the variables, the program asks for the user fullname using Scanner class and it's method .nextLine (the variable 'name' will save the user input). A while loop is also used to iterate over the name, taking character by character with the method .charAt, the program will append letters in subName until it finds a space only then the content of subName will be transfer to reversedName and the content of subName will be deleted, then the program continues with the process until the end of the for loop; finally, the program places the content of subName at the beginning of reversedName, and print the result transforming the StringBuilder to a normal string.