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Marat540 [252]
3 years ago
6

Think of an employee object. What are several of the possible states that the object may have over time?

Engineering
1 answer:
borishaifa [10]3 years ago
4 0

Hi, your question is unclear. However, I inferred you meant 'object' in computer programming.

Explanation:

Remember, the term 'object' used in programming refers to stored data that can take different forms or states.

For example, a company's employee database may have several object states. Which includes;

  1. New Employee (meaning the database can contain newly employed employees)
  2. Former Employee (meaning the database can contain past/formerly employed employee)
  3. Current Employee (meaning the database can contain present/current employees)
  4. Suspended Employee (meaning the database could contain employees on suspension)

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Material with hardness of 220 Vickers is harder than material with a hardness of 180 Vickers. a)-True b)- False
PSYCHO15rus [73]

Answer:

Correct option a) True.

Explanation:

It is true since the Vickers hardness value refers to the force applied in a 136 ° diamond tip penetrator divided by the surface of the groove produced in the material, the lower the impression made on this greater the value will be end of the Vickers measurement and greater its hardness.

The equation to determine the Vickers hardness value will be:

Hv= ((1.854 × P)/(d²))  (kg/mm²)

Therefore a value of 220 Vickers refers to a harder material than another value of 180 Vickers.

6 0
3 years ago
A proposed piping and pumping system has 20-psig static pressure, and the piping discharges to atmosphere 160 ft above the pump.
larisa86 [58]

Answer: (B) 100

Explanation:

Given that;

Pstatic = 20 psig , hz = 160ft, hf = 20ft

Now total head will be;

T.h = hz + hf

T.h= 160 + 20

T.h = 180ft

Minimum pressure = Psatic + egh

we know that specific weight of water is 62.4 (lb/ft3)

so

P.min = (20 bf/in² ) + (62.4 b/ft³ × 180 fr

P.min = (20 bf/in² ) + ( 62.4 × 180 × 1 ft²/144 in²)

P.min = 20 + 78

P.min = 98 lbf/in²

Therefore the minimum pressure rating (psi) of the piping system is most nearly B) 100

7 0
3 years ago
At a certain location, wind is blowing steadily at 7 m/s. Determine the mechanical energy of air per unit mass and the power gen
Kaylis [27]

Answer:

Explanation:

From the information given;

The velocity of the wind blow V = 7 m/s

The diameter of the blades  (d) = 80 m

Percentage of the overall efficiency \eta_{overall} = 30\%

The density of air \rho = 1.25 kg/km^3

Then, we can use the concept of the kinetic energy of the wind blowing to estimate the mechanic energy of air per unit mass by using the formula:

e_{mechanic} = \dfrac{mV^2}{2}

here;

m = \rho AV

= 1.25 \times \dfrac{\pi}{4}(80)^2 \times 7

= 43982.29 kg/s

∴

W = e_{mechanic} = \dfrac{mV^2}{2}

= \dfrac{43982.29 \times 7^2}{2}

= 1077566.105 \ W

\mathbf{ =1077.566 \ kW}

The actual electric power is:

W_{electric} = \eta_{overall} \times W

W_{electric} = 0.3 \times 1077.566

\mathbf{W_{electric} =323.26 \ kW}

8 0
2 years ago
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vladimir2022 [97]
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