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3 years ago

9. If a car travels 18,000 meters in 30 minutes, what is its average speed?

Physics

1 answer:

MrRa [10]3 years ago

5 0

Answer:

10m/s

Hope this helps!

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What is the magnitude of the gravitational force of attraction between two 0.425-kilogram soccer balls when the distance between

Lapatulllka [165]

<u>Answer</u>

4.8212×10⁻¹¹ N

<u>Explanation</u>

The gravitational force F, between 2 masses m₁ and m₂ is given by:

F = (Gm₁m₂)/d²

Where G = 6.673 x 10⁻¹¹ N m²/kg² and d is the distance between the 2 masses.

F = (Gm₁m₂)/d²

= (6.673 x 10⁻¹¹ × 0.425 × 0.425)/0.500²

= 1.2053×10⁻¹¹/0.25

= 4.8212×10⁻¹¹ N

7 0

3 years ago

The main reason for making the cover of a vacuum

prohojiy [21]

Answer:

(A) conduction

Explanation:

parts of that are touching other parts and thus create heat!!!! dont lose that heat!

7 0

3 years ago

The overgrowth of algae on the surface of this water is caused by

Mekhanik [1.2K]

The process is called Eutrophication, the two main nutrients that cause eutrophication are nitrogen and phosphorus

3 0

2 years ago

PHYSICS

quester [9]

Answer:

c) 8.3 x 10^24 molecules

Explanation:

First of all, we convert the volume of the glass of water from mL to $cm^3$ :

$V=250 mL = 250 cm^3$

The relationship between mass and volume is:

$d=\frac{M}{V}$

where

$d=1.00 g/cm^3$ is the density of water

M is the total mass of the glass of water

$V=250 cm^3$ is the volume of the water in the glass

Solving for M,

$M=dV=(1.00)(250)=250 g = 0.250 kg$

Now we know that the mass of a single molecule of water is

$m=3.0\cdot 10^{-26}kg$

The total mass of the water in the glass can be written as

$M=Nm$

where

N is the number of molecules in the glass of water

Solving for N, we find:

$N=\frac{M}{m}=\frac{0.250}{3.0\cdot 10^{-26}}=8.3\cdot 10^{24}$

7 0

3 years ago

Heptane and water do not mix, and heptane has a lower density (0.684 g/mL) than water (1.00 g/mL). A graduated cylinder contains

lakkis [162]

Given that the density of heptane is

$d_h=\frac{0.684g}{mL}$

The mass of heptane is

$m_h=31\text{ g}$

The density of water is

$d_w=\frac{1g}{mL}$

The mass of water is

$m_w=37\text{ g}$

The volume of heptane will be

$\begin{gathered} V_h=\frac{m_h}{d_h} \\ =\frac{31}{0.684} \\ =45.32\text{ mL} \end{gathered}$

The volume of water will be

$\begin{gathered} V_w=\frac{m_w}{d_w} \\ =\frac{37}{1} \\ =37\text{ mL} \end{gathered}$

Thus, the volume of heptane is 45.32 mL and the volume of water is 37 mL.

The total volume of liquid in the cylinder will be

$\begin{gathered} V=V_h+V_w \\ =45.32+37 \\ =82.32\text{ mL} \end{gathered}$

The total volume of liquid in the cylinder will be 82.32 mL.

7 0

11 months ago