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Usimov [2.4K]
3 years ago
11

Can you please solve this for me urgently want to make sure if my answers are correct?

Physics
1 answer:
GenaCL600 [577]3 years ago
4 0
Ok, but where’s the question?
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Two in-phase loudspeakers are placed along a wall and are separated by a distance of 4.00 m. They emit sound with a frequency of
Slav-nsk [51]

Answer: 0.729 m

Explanation:

In order to be able to hear a constructive interference, the difference between the distances from both speakers to the person must be a multiple of the wavelength of the sound.

We can find out the wavelength as we know the value of the frequency and the sound speed, as follows:

λ = v / f = 343 m/s / 514 Hz = 0.67 m.

So, if we call x to the distance perpendicular to the wall, right front of the left speaker, and h to the distance to the right speaker, we can write the following expression:

h – x = n λ (1)

As x, h, and the distance d between speakers determine a square triangle, we can apply Pitheagoras ‘theorem, as follows:

h2 = d2 + x 2

h2 – x2  = d2 (2)

(h+x)(h-x) = d2 (3)

Dividing both sides in (3) and (1), we get:

h + x = d2 / n λ (4)

Substracting both sides in (4) and (1), we have:

2 x = (d2/ n λ) - n λ = (d2 – n2 λ2) / 2 n λ  (5)

We must choose the maximum value for n that satisfies x>0, as follows:

nmax = d / λ = 5.7 → nmax = 5

Solving for x, and replacing for the values of d, λ and n in (5), we get:

x = 16 – 25. (0.67)2 / 2.5.(0.67) = 0.729 m

Explanation:

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Gravity changes depending on latitude, as well as height above sea level.
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