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2 years ago

What is the average of the speed of light

Physics

2 answers:

ASHA 777 [7]2 years ago

8 0

186,282 miles per second (299,792 kilometers per second

Maslowich2 years ago

6 0

The average speed of light is 186,000 mph

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How much force is needed to accelerate a toy car of mass 8 kg at 2m/s

atroni [7]

Answer:

Explanation:

f = ma

8kg x 2m/s = 4N

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2 years ago

4. A helicopter is flying at a height of 1.5km. If it has 50MJ of G.P.E., what is the mass of the

lapo4ka [179]

Its its tony lopez

explanation

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3 years ago

The maximum tension the wire can withstand without breaking is 300 N . A 0.800 kg projectile traveling horizontally hits and emb

topjm [15]

Answer:

Let's investigate the case where the cable breaks.

Conservation of angular momentum can be used to find the speed.

$\vec{L}_1 = \vec{L}_2\\\vec{L}_1 = m\vec{v_0} \\\vec{L}_2 = I\vec{\omega}\\$

The projectile embeds itself to the ball, so they can be treated as a combined object. The moment of inertia of the combined object is equal to the sum of the moment of inertia of both objects.

$I = I_{projectile} + I_{ball}\\I = mr^2 + mr^2\\I = 2mr^2$

where r is the length of the cable.

After the collision, the ball and the projectile makes a circular motion because of the cable. So, the force (tension) in circular motion is

$F = \frac{mv^2}{r}$

The relation between linear velocity and the angular velocity is

$v = \omega r$

So,

$F = \frac{m(\omega r)^2}{r} = m\omega^2 r = 300\\mv_0r =I\omega\\\\\omega = mv_0r/I\\300 = m(\frac{mv_0r}{I})^2r = m(\frac{mv_0r}{2mr^2})^2r = m(\frac{v_0}{2r})^2r = \frac{mv_0^2r}{4r^2} = \frac{mv_0^2}{4r}\\300 = \frac{0.8v_0^2}{4r}\\1500 = v_0^2/r\\v_0 = \sqrt{1500r}$

As can be seen, the maximum velocity for the projectile without breaking the cable is $\sqrt{1500r}$ , where r is the length of the cable.

6 0

3 years ago

Train car A is at rest when it is hit by train car B. The two cars, which have the same mass, stick together and move off after

Natali [406]

Answer:C The final velocity is half of trained car B's initial velocity.

Explanation:

7 0

2 years ago

Read 2 more answers

The velocity - time graph of a ball of mass 25g moving on road is as given below:

lana [24]

Assume that the ball rolls to the right.

From the velocity-time graph, the acceleration is
a = (0 - 10 m/s)/(4 - 0 s) = -2.5 m/²

Part (a)
Because the mass of the ball is 25g or 0.025 kg, the force that the road exerts on the ball is
F = (0.025 kg)*(-2.5 m/s²) = -0.0625 N
The force is negative because it acts in opposition to the motion of the ball.

Answer: 0.0625 N to the left.

Part (b)
The direction of the force exerted by the road is to the left because it opposes the motion of the ball to the right.

Part (c)
The unit force is 1 N (Newton), with the dimension (kg-m)/s².

3 0

2 years ago