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2 years ago

Consider the function f(n) = n

Engineering

1 answer:

alexira [117]2 years ago

4 0

get off this

Explanation:

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Certain pieces made by an acoustic lathe are subject to three kinds of defects X,Y,Z. A sample of 100 pieces was inspected with

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Explanation:

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3 years ago

Thermodynamics deals with the macroscopic properties of materials. Scientists can make quantitative predictions about these macr

Arlecino [84]

Answer:

Explanation:

From the information given:

Using the equipartition theorem, the average energy of a molecule dor each degree of freedom is:

$U = \dfrac{1}{2}k_BT$

$U = \dfrac{1}{2}nRT$

For s degree of freedom

$U = \dfrac{1}{2}snRT$

However, the molar specific heat $C_v = \dfrac{1}{n} \dfrac{dU}{dT}$

Therefore, in terms of R and s;

$C_v = \dfrac{1}{n} \dfrac{d}{dT} \begin{pmatrix} \dfrac{1}{2} snRT \end {pmatrix}$

$C_v = \dfrac{Rs}{2}$

Given that:

Cv=70.6Jmol⋅K and R=8.314Jmol⋅K

Then; using the formula $C_v = \dfrac{Rs}{2}$

$70.6 \ J/mol.K = \dfrac{(8.314 \ J/mol.K)\times s}{2}$

$70.6 \ J/mol.K \times 2= (8.314 \ J/mol.K)\times s$

$s= \dfrac{70.6 \ J/mol.K \times 2}{ (8.314 \ J/mol.K) }$

s = 16.983

s $\simeq$ 17

7 0

3 years ago

Engineered lumber should not be used for

Dimas [21]

Answer:

Composite panel garage doors

Explanation:

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2 years ago

The specific volume of mercury is .00007 m^3/Kg. What is its density in lbm/ft^3?

aalyn [17]

Answer:

891.027 lbm/ft³

Explanation:

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5 0

3 years ago

An aquifer has three different formations. Formation A has a thickness of 8.0 m and hydraulic conductivity of 25.0 m/d. Formatio

saveliy_v [14]

Answer:

The horizontal conductivity is 41.9 m/d.

The vertical conductivity is 37.2 m/d.

Explanation:

Given that,

Thickness of A = 8.0 m

Conductivity = 25.0 m/d

Thickness of B = 2.0 m

Conductivity = 142 m/d

Thickness of C = 34 m

Conductivity = 40 m/d

We need to calculate the horizontal conductivity

Using formula of horizontal conductivity

$K_{H}=\dfrac{H_{A}K_{A}+H_{A}K_{A}+H_{A}K_{A}}{H_{A}+H_{B}+H_{C}}$

Put the value into the formula

$K_{H}=\dfrac{8.0\times25+2,0\times142+34\times40}{8.0+2.0+34}$

$K_{H}=41.9\ m/d$

We need to calculate the vertical conductivity

Using formula of vertical conductivity

$K_{V}=\dfrac{H_{A}+H_{B}+H_{C}}{\dfrac{H_{A}}{K_{A}}+\dfrac{H_{B}}{K_{B}}+\dfrac{H_{C}}{K_{C}}}$

Put the value into the formula

$K_{V}=\dfrac{8.0+2.0+34}{\dfrac{8.0}{25}+\dfrac{2.0}{142}+\dfrac{34}{40}}$

$K_{V}=37.2\ m/d$

Hence, The horizontal conductivity is 41.9 m/d.

The vertical conductivity is 37.2 m/d.

3 0

3 years ago