Consider the function f(n) = n

If gain of the critically damped system is increased, the system will behave as a) Under damped b) Over damped c) Critically dam

Ganezh [65]

Answer:

a) Under damped

Explanation:

Given that system is critically damped .And we have to find out the condition when gain is increased.

As we know that damping ratio given as follows

$\zeta =\dfrac{C}{C_c}$

Where C is the damping coefficient and Cc is the critical damping coefficient.

$C_c=2\sqrt{mK}$

So from above we can say that

$\zeta =\dfrac{C}{2\sqrt{mK}}$

$\zeta \alpha \dfrac{1}{\sqrt K}$

From above relationship we can say when gain (K) is increases then system will become under damped system.

7 0

3 years ago

Convert

Helen [10]

Answer:

(a) $1.308\times 10^{-4}m/sec$

(b)57.33831 pound/cubic feet

(c)120.1095 hp

Explanation:

We have

(a) 760 miles / hour

We know that $1\ mile\ =0.00062m$

And 1 hour = 60×60=3600 sec

So $760miles/hour=\frac{760\times 0.00062meter}{3600sec}=1.308\times 10^{-4}m/sec$

(b) 927 kg/cubic meter to mass/cubic foot

We know that 1 kg = 2.20 pound

So 921 kg = 921×2.20=2026.2 pound

We know that 1 cubic meter = 35.31 cubic feet

So 57.33831 pound / cubic feet

(c) We have to convert to hp

$5.37\times 10^3kj/min=\frac{5.37\times 1000kj}{60sec}=89.5kj/sec$

We know that 1 kj /sec = 1.341 hp

So 89.5 kj/sec = 89.5××1.341=120.1095 hp

7 0

4 years ago

(2pts) In _______________, the pulse amplitude is made proportional to the amplitude of the modulating signal. pulse-amplitude m

Reptile [31]

Answer:

(a) pulse-amplitude modulation (PAM)

Explanation:

It should be no surprise that pulse amplitude is modulated in <em>pulse-amplitude modulation (PAM)</em>.

7 0

3 years ago

1. When two vehicles moving at the same speed are involved in a collision, the vehicle that

GenaCL600 [577]

Answer:

that has

Explanation:

more weight may cause a strong hit

8 0

3 years ago

Technician A says that tire markings now include load ratings on tires. Technician B says that they are only included on truck t

Ludmilka [50]

Technician A is correct hope this helps

5 0

3 years ago