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MAVERICK [17]
3 years ago
14

Consider the function f(n) = n

Engineering
1 answer:
alexira [117]3 years ago
4 0

get off this

Explanation:

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Explain how does optimism and open-minded can help engineers succeed at their jobs
Aleonysh [2.5K]

Answer:There is an idea floating around that being an optimist is good for you. In her book, ‘Smile or Die’, Barbara Ehrenreich traces the origins of this idea, from early religious eccentrics to modern day psychology and motivational gurus. Related notions are that self belief is important to achievement, that confidence is needed, and you get what you expect. I freely admit that there was a time when I also thought that expectations influenced results, and sometimes they do.

However, since then I have examined this much more closely and changed my views. I now realise that there are downsides to optimism too, and that optimism and pessimism are not the only options. If you are interested in exploring this in more detail, especially if you have been uncomfortable with the self-delusion that positive thinking usually involves, then this article may provide a clearer understanding of a reasonable alternative that works and makes sense.

What is the choice?

Research has fairly consistently shown two biases in our predictions about the net benefits of actions we plan to take: (1) on average our predictions are usually too high, and (2) when asked to give ranges for our predictions our ranges tend to be too narrow.

This gives a useful insight into some familiar mental outlooks that we might try to adopt:

Pessimism: Expecting unrealistically low net benefits from courses of action (i.e. poor results achieved, if at all, after a struggle), and being unrealistically sure that those poor benefits will be achieved.

Optimism: Expecting unrealistically high net benefits from courses of action (i.e. great results easily achieved), and being unrealistically sure that those great benefits will be achieved.

Both of these involve overly narrow predictions. If we correct that by being more open-minded then other possible outlooks emerge. The one I will focus on in this article is this:

Open-minded realism: Having a view of the results of courses of action that is not biased towards high or low net benefits, and is open to a range of possibilities in a way that is, again, rational and unbiased, rather than overly narrow.

Here's a picture that shows each of these outlooks. The horizontal axis represents the outcome of some course of action, ranging from terrible on the left to great on the right. The height of the graphs represents the person's belief that each level of outcome will occur. Pessimism is narrow and negative, represented by the red distribution. Optimism is narrow and positive, represented by the green distribution. Open-minded realism, represented by the black curve, is unbiased and more spread, reflecting an open mind about what might happen.

Explanation:

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2 years ago
what problem was the team presented within this episode? What problem mine they have thought they should solve if they hadn’t li
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Explanation:

whats

the question choices

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3 years ago
For an AC machine, what percentage of power is at the negative terminal?
aivan3 [116]
B, it should be somewhere in the 60s I believe
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3 years ago
Anyone please help me with this
Advocard [28]
The last one lithium
4 0
3 years ago
A construction company distributes its products by trucks loaded at its loading station. A backacter in conjunction with trucks
blagie [28]

Answer:

a) L = 1.5

L_q = 0.9

W =  \dfrac{1 }{8 } \, hour

W_q =  \dfrac{3}{40 } \, hour

P = \dfrac{3}{5 }

b) The new backacter should be recommended

c) The additional backacter should not be deployed

Explanation:

a) The required parameters are;

L = The number of customers available

L = \dfrac{\lambda }{\mu -\lambda }

μ = Service rate

L_q = The number of customers waiting in line

L_q = p\times L

W = The time spent waiting including being served

W = \dfrac{1 }{\mu -\lambda }

W_q = The time spent waiting in line

W_q = P \times W

P = The system utilization

P = \dfrac{\lambda }{\mu  }

From the information given;

λ = 12 trucks/hour

μ = 3 min/truck = 60/3 truck/hour = 20 truck/hour

Plugging in the above values, we have;

L = \dfrac{12 }{20 -12 } = \dfrac{12 }{8 } = 1.5

P = \dfrac{12 }{20 } = \dfrac{3}{5 }

L_q = \dfrac{3}{5 } \times \dfrac{3}{2 } = \dfrac{9}{10 } = 0.9

W = \dfrac{1 }{20 -12 } =  \dfrac{1 }{8 } \ hour

W_q = \dfrac{3}{5 } \times \dfrac{1}{8 } = \dfrac{3}{40 } \, hour

(b) The service rate with the new backacter = 1.5 minutes/truck which is thus;

μ = 60/1.5 trucks/hour = 40 trucks/hour

P = \dfrac{12 }{40  } = \dfrac{3}{10}

W = \dfrac{1 }{40 -12 } =  \dfrac{1 }{38 } \, hour

W_q = \dfrac{3}{10 } \times \dfrac{1}{38 } = \dfrac{3}{380 } \, hour

λ = 12 trucks/hour

Total cost = mC_s + \lambda WC_w

m = 1

C_s = GH¢ = 1300

C_w = 400

Total cost with the old backacter is given as follows;

1 \times 1000 + 12 \times \dfrac{1}{8}  \times 400 = \$ 1,600.00

Total cost with the new backacter is given as follows;

1 \times 1300 + 12 \times \dfrac{1}{38}  \times 400 = \$ 1,426.32

The new backacter will reduce the total costs, therefore, the new backacter is recommended.

c)

Here μ = 3 min/ 2 trucks = 2×60/3 truck/hour = 40 truck/hour

\therefore W = \dfrac{1 }{40 -12 } =  \dfrac{1 }{38 } \, hour

Total cost with the one backacter is given as follows;

1 \times 1000 + 12 \times \dfrac{1}{8}  \times 400 = \$ 1,600.00

Total cost with two backacters is given as follows;

2 \times 1000 + 12 \times \dfrac{1}{38}  \times 400 = \$ 2,126.32

The additional backacter will increase the total costs, therefore, it should not be deployed.

6 0
3 years ago
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