Solution :
Given data is :
Density of the milk in the tank,
Length of the tank, x = 9 m
Height of the tank, z = 3 m
Acceleration of the tank,
Therefore, the pressure difference between the two points is given by :
Since the tank is completely filled with milk, the vertical acceleration is
Therefore substituting, we get
Therefore the maximum pressure difference in the tank is Δp = 47.87 kPa and is located at the bottom of the tank.
In a cell, protein synthesis is the primary function of the ribosomes, found in both eukaryotic and prokaryotic cells.
A Ribosome is a cell organelle that makes protein. The location of the ribosome in a cell determine the kind of protein it makes. If the ribosome is attached to the endoplasmic reticulum, the proteins made are utilized both within and outside the cell. If the ribosome is in the cytoplasm, floating freely, then the kind of protein made will be utilized within the cell only.
Answer:
B) t = 1.83 [s]
A) y = 16.51 [m]
Explanation:
To solve this problem we must use the following equation of kinematics.
where:
Vf = final velocity = 0
Vo = initial velocity = 18 [m/s]
g = gravity acceleration = 9.81 [m/s²]
t = time [s]
Note: the negative sign in the above equation means that the acceleration of gravity is acting in the opposite direction to the motion.
A) The maximum height is reached when the final velocity of the ball is zero.
0 = 18 - (9.81*t)
9.81*t = 18
t = 18/9.81
t = 1.83 [s], we found the answer for B.
Now using the following equation.
where:
y = elevation [m]
Yo = initial elevation = 0
y = 18*(1.83) - 0.5*9.81*(1.83)²
y = 16.51 [m]
Answer:
1.) 274.5v
2.) 206.8v
Explanation:
1.) Given that In one part of the lab activities, students connected a 2.50 µF capacitor to a 746 V power source, whilst connected a second 6.80 µF capacitor to a 562 V source.
The potential difference and charge across EACH capacitor will be
V = Voe
Where Vo = initial voltage
e = natural logarithm = 2.718
For the first capacitor 2.50 µF,
V = Vo × 2.718
746 = Vo × 2.718
Vo = 746/2.718
Vo = 274.5v
To calculate the charge, use the below formula.
Q = CV
Q = 2.5 × 10^-6 × 274.5
Q = 6.86 × 10^-4 C
For the second capacitor 6.80 µF
V = Voe
562 = Vo × 2.718
Vo = 562/2.718
Vo = 206.77v
The charge on it will be
Q = CV
Q = 6.8 × 10^-6 × 206.77
Q = 1.41 × 10^-3 C
B.) Using the formula V = Voe again
165 = Vo × 2.718
Vo = 165 /2.718
Vo = 60.71v
Q = C × 60.71
Q = C
Answer:
<h2>400 J</h2>
Explanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 100 × 4
We have the final answer as
<h3>400 J</h3>
Hope this helps you