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jeka94
3 years ago
12

A

Physics
1 answer:
siniylev [52]3 years ago
5 0
C is the correct answer hope this helps :)
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A 150kg person stands on a compression spring with spring constant 10, 000 N/m and norminal.Length of 0.50.What is the togal len
Eva8 [605]

Answer:

Total length of spring 0.647 m

Explanation:

We have given mass of the person m = 150 kg

Acceleration due to gravity g=9.8m/sec^2

Spring constant k = 10000 N/m

Nominal length of spring = 0.50

According to hook's law

mg=kx

150\times 9.8=10000\times x

x = 0.147 m

So total length of spring = 0.50+0.147 = 0.647 m

4 0
3 years ago
A sample of glass has a mass of 15 g and takes up 14.3 cm 3 of space. What is the density? If you drop a piece of the same glass
mr Goodwill [35]
The density will be 1.05
The mass will be 13.65
3 0
4 years ago
A copper wire of resistivity 2.6 × 10-8 Ω m, has a cross sectional area of 35 × 10-4 cm2
KengaRu [80]

Answer:

the length of the wire is 134.62 m.

Explanation:

Given;

resistivity of the copper wire, ρ = 2.6 x 10⁻⁸ Ωm

cross-sectional area of the wire, A  = 35 x 10⁻⁴ cm² = ( 35 x 10⁻⁴) x 10⁻⁴ m²

resistance of the wire, R = 10Ω

The length of the wire is calculated as follows;

R = \frac{\rho L}{A} \\\\L = \frac{RA}{\rho} \\\\L= \frac{10 \times (35\times 10^{-4}) \times 10^{-4}}{2.6 \times 10^{-8}} \\\\L = 134.62 \ m

Therefore, the length of the wire is 134.62 m.

6 0
3 years ago
The sides of a rectangle are 6.01 meters and 12 meters. Taking the significant figures into account, what is the area of the rec
Anit [1.1K]

Answer: The area of the rectangle is 72.12 square meters

Explanation:

The area of the rectangle is  length x width  

Area = 6.01 m x 12 m = 72.12 m²

4 0
3 years ago
Why can’t you use a model to learn everything about an object?
goldenfox [79]

Answer:Models have always been important in science and continue to be used to test hypotheses and predict information. Often they are not accurate because the scientists may not have all the data. It is important that scientists test their models and be willing to improve them as new data comes to light.

Explanation:

3 0
4 years ago
Read 2 more answers
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