3 years ago

A

Physics

1 answer:

siniylev [52]3 years ago

5 0

C is the correct answer hope this helps :)

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Nancy is pushing her empty grocery cart at a rate of 1.8 m/s. 30 seconds later,

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1. An electron (Q=16x10^-20 C, m=1x10^-30 kg) moving at half a megameter per second up the page enters a region with a uniform m

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Explanation:

It is given that,

Charge on electron, $q=16\times 10^{-20}\ C$

Mass of the electron, $m=9.1\times 10^{-31}\ kg$

Speed of the electron, $v=0.5\ Mm/s=0.5\times 10^6\ m/s$

Magnetic field, B = 1 T (directed out of the page)

Let F is the magnetic force acting on the electron. It is given by :

$F=qvB\ sin\theta$

Here, $\theta=90^{\circ}$

$F=qvB$

$F=16\times 10^{-20}\ C\times 0.5\times 10^6\ m/s\times 1\ T$

$F=8\times 10^{-14}\ N$

Using the right hand rule, the direction of magnetic force is upward to the plane of the paper. Also, the electron will follow the circular path. It is given by :

$r=\dfrac{mv}{qB}$

$r=\dfrac{9.1\times 10^{-31}\ kg\times 0.5\times 10^6\ m/s}{16\times 10^{-20}\ C\times 1\ T}$

$r=2.84\times 10^{-6}\ m$

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3 years ago

The distance from the earth to the moon is 3.84 x10^8 m. if a spaceship traveled from the earth at a speed of 950 mpr how many d

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4 years ago

How much force does it take to bring a 1,050 N car from rest to a velocity of 42 m/s in 13 seconds?

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Answer:

F = 339.23 N

Explanation:

Weight of a car, W = 1050 N

Initial velocity, u = 0

Final velocity, v = 42 m/s

Time, t = 13 s

The weight of an object is given by :

W = mg

g is the acceleration due to gravity

$m=\dfrac{W}{g}\\\\m=\dfrac{1050}{10}\\\\m=105\ kg$

The force acting on car is :

$F=ma\\\\F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{105\times (42-0)}{13}\\\\F=339.23\ N$

So, the force acting on the car is 339.23 N.

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