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lesya [120]
3 years ago
14

A plane flying horizontally at 384 m/s releases a package at an altitude of 15,721 m.

Physics
1 answer:
Nataly [62]3 years ago
3 0

Answer:

t = 56.6 s

Explanation:

In the absence of air resistance we can use the kinematic equation

s = ½at²

The package is at vertical rest at the drop point. The horizontal velocity will not matter.

t = √(2s/a)

t = √(2(15721)/9.81)

t = 56.6 s

With air resistance, the time will likely be significantly longer as terminal velocity probably has  been achieved.

Without air resistance, the velocity at ground impact would be

v = at = 9.81(56.6) = 555 m/s

which is almost double the speed of sound in air, so air resistance is not negligible.

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7. A mother pushes her 9.5 kg baby in her 5kg baby carriage over the grass with a force of 110N @ an angle
jasenka [17]

Weight of the carriage =(m+M)g =142.1\ N

Normal force =Fsin(\theta) + W = 197.1\ N

Frictional force =\mu N=27.59\ N

Acceleration =4.66\ m\ s^{-2}

Explanation:

We have to look into the FBD of the carriage.

Horizontal forces and Vertical forces separately.

To calculate Weight we know that both the mass of the baby and the carriage will be added.

  • So Weight(W) =(m+M)\times g =(9.5+5)\ kg \times 9.8 =142.1\ Newton\ (N)

To calculate normal force we have to look upon the vertical component of forces, as Normal force is acting vertically.We have weight which is a downward force along with F_x, force of 110\ N acting vertically downward.Both are downward and Normal is upward so Normal force =Summation\ of\ both\ forces

  • Normal force (N) = Fsin(\theta)+W=110sin(30) + 142.1 =197.1\ N
  • Frictional force (f) =\mu N=0.14\times 197.1 =27.59\ N

To calculate acceleration we will use Newtons second law.

That is Force is product of mass and acceleration.

We can see in the diagram that F_y=Horizontal and F_x=Vertical component of forces.

So Fnet = Fy(Horizontal) - f(friction) = m\times a

  • Acceleration (a) =\frac{Fcos(\theta)-\mu N}{mass(m)} =\frac{(95.26-27.59)}{14.5}= 4.66\ m\ s{^2 }

So we have the weight of the carriage, normal force,frictional force and acceleration.

3 0
3 years ago
How much time does it take a dropped object to fall 180 m on Earth?
rusak2 [61]

Answer:

6s

Explanation:

Assume it is dropped from rest and the gravitational acceleration is 10

By the equation of motion under constant acceleration:

s=ut+\frac{1}{2} at^2

180 = (0)t+10(t^2)/2

t = 6 or -6 (rejected)

t = 6 s

7 0
3 years ago
The distance between adjacent nodes in a standing wave pattern in a length of string is 25.0 cm:A. What is the wavelength of wav
mina [271]

A) 50 cm

B) 10000 cm/s

Explanation

Step 1

A)

If you know the distance between nodes and antinodes then use this equation:

\begin{gathered} \frac{\lambda}{2}=D \\ \text{where}\lambda\text{ is the wavelength} \\ D\text{ is the distance betw}een\text{ nodes} \end{gathered}

then, let

D=\text{ 25 cm }

now, replace to find the wavelength

\begin{gathered} \frac{\lambda}{2}=25 \\ \text{Multiply both sides by 2} \\ \frac{\lambda}{2}\cdot2=25\cdot2 \\ \lambda=50\text{ Cm} \end{gathered}

so, the wavelength is

A) 50 cm

Step 2

The speed of a wave can be found using the equation

v=\lambda f

or velocity = wavelength x frequency,

then,let

\begin{gathered} \lambda=50\text{ cm} \\ f=200\text{ Hz} \end{gathered}

replace and evaluate

\begin{gathered} v=\lambda f \\ v=50\text{ cm }\cdot200\text{ HZ} \\ v=10000\text{ }\frac{\text{cm}}{s} \end{gathered}

so

B) 10000 cm/s

I hope this helps you

6 0
1 year ago
If you hold your hand over a pot of boiling water, it feels hot. Explain how the boiling water is transforming heat to your hand
MakcuM [25]

I don't no if this helps but the body heat from your hand causes the liquid to boil, which in turn makes the liquid evaporate, turning it to gas. The expanding gas pushes the liquid upwards and when you release your hand, equilibrium is re-established.


8 0
3 years ago
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In this type of bond, electrons are lost or gained by atoms, and the atoms are held together by electrical attraction.
expeople1 [14]
<span>In Ionic type of bonding, electrons are lost (more protons than electrons and positive charge) or gained (more electrons than protons, still a negative charge) by atoms, and the atoms are held together by electrical attraction in the process. Covalent bondings are the sharing of electrons as well as partial bondings. Covalent bondings’ electrons have the same charges thus, there is no gaining or losing electrons in the process of sharing. Strong bondings are applicable only to Hydrogen (H) atoms. </span>
8 0
3 years ago
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