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Aleonysh [2.5K]
3 years ago
6

How many hours are in a month of 30 days?

Physics
1 answer:
madam [21]3 years ago
7 0
720 hours in a month of 30 days
You might be interested in
Worksheet
saw5 [17]

Answer:

i cant see the ??

Explanation:

3 0
2 years ago
Another engine reaches its top speed in 7.5s. It is able to perform 250,000 J of wok in that time. How much power this engine ha
EastWind [94]

Answer:

33,333.3J/s

Explanation:

Energy expended which is the work done in Joule

=250,000J

Time taken to expend the energy =7.5s

Power =Unknown

Formula

Power = <u> </u><u> </u><u> </u><u> </u><u> </u><u>Work</u><u> </u><u> </u><u> </u>

Time

Hence, Power = <u>250,000J</u>

7.5s

Power = 33,333.3J/s

3 0
2 years ago
You are given two vectors vector A = 4.9 at 31o vector B = 6 at 156o Angles are measured counterclockwise from the x-axis. What
Ket [755]

Answer:

   C_{y} = 4.96  and     θ' = 104,5º

Explanation:

To add several vectors we can decompose each one of them, perform the sum on each axis, to find the components of the resultant and then find the module and direction.

Let's start by decomposing the two vectors.

Vector A

             sin θ = A_{y} / A

             cos θ = Aₓ / A

             A_{y} = A sin  θ

             Ax = A cos θ

             A_{y} = 4.9 sin 31 = 2.52

             Ax = 4.9 cos 31 = 4.20

Vector B

           B_{y} = B sin θ

           Bx = B cos θ

           B_{y} = 6 sin 156 = 2.44

           Bx = 6 cos 156 = -5.48

The components of the resulting vector are

X axis

         Cx = Ax + B x

         Cx = 4.20 -5.48

         Cx = -1.28

Axis y

         C_{y} = Ay + By

         C_{y} = 2.52 + 2.44  

         C_{y} = 4.96

Let's use the Pythagorean theorem to find modulo

         C = √ (Cₙ²x2 + Cy2)

         C = Ra (1.28 2 + 4.96 2)

         C = 5.12

We use trigonemetry to find the angle

         tan θ = C_{y} / Cₓ

          θ’ = tan⁻¹ (4.96 / (1.28))

           θ’ = 75.5

como el valor de Cy es positivo y Cx es negativo el angulo este en el segundo cuadrante, por lo cual el angulo medido respecto de eje x positivo es

       θ’ = 180 – tes

        θ‘= 180 – 75,5

        θ' = 104,5º

7 0
3 years ago
In an inelastic collision, which of the following statements is always true?
xz_007 [3.2K]
Well C is definitely one of the correct answers.
8 0
3 years ago
As a laudably skeptical physics student, you want to test Coulomb's law. For this purpose, you set up a measurement in which a p
monitta

Answer:

force F = 1.66 × 10^{-13} N

Explanation:

given data

proton and an electron = 865 nm

solution

we get here force that is express as

force F = k q1 q2 ÷ r²      ......................1

put here value and we get

force F = 9 × 10^{9} × \frac{1.6\times (10^{-19})^{2}}{865 \times (10^{-9})^{2}}    

force F = 1.66 × 10^{-13} N

4 0
3 years ago
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