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Aleonysh [2.5K]
3 years ago
6

How many hours are in a month of 30 days?

Physics
1 answer:
madam [21]3 years ago
7 0
720 hours in a month of 30 days
You might be interested in
A net force of 500 N acts on a 100 kg cart. What is the acceleration of the cart if the mass is doubled?
oksian1 [2.3K]

Answer:

2.5 m/s²

Explanation:

You can solve the following equation: F=ma for acceleration.

You'll be left with this:

a=F/m

And then you substitute the force and the doubled mass

a=500N/200kg

a=2.5 m/s²

8 0
2 years ago
By how much does the pressure of a gas in a rigid vessel decrease when the temperature drops from 0 ∘C to –1∘C?
Ugo [173]
When a problem says a rigid vessel, it means that volume is constant. At constant V, pressure and temperature are indirectly proportional. We calculate as follows:

P1/T1 = P2/T2
P1/P2 = T1/T2
P1/P2 = 273.15 / 272.15
P1/P2 = 1.00

Hope this helps. Have a nice day.
7 0
3 years ago
How to do this question?​
Zigmanuir [339]

Answer:

First.

  • Find double diffrenciation of all equation
  • Then put the value of t in the differenciated equations
3 0
3 years ago
In 2 1/2 hours an airplane travels 1150 km against the wind. It takes 50 min to travel 450 km with the wind. Find the speed of t
Tamiku [17]

Answer:

Velocity of airplane is 500 km/h

Velocity of wind is 40 km/h

Explanation:

V_a= Velocity of airplane in still air

V_w= Velocity of wind

Time taken by plane to travel 1150 km against the wind is 2.5 hours

V_a-V_w=\frac {1150}{2.5}\\\Rightarrow V_a-V_w=460\quad (1)

Time taken by plane to travel 450 km against the wind is 50 minutes = 50/60 hours

V_a+V_w=\frac {450}{50}\times 60\\\Rightarrow V_a-V_w=540\quad (2)

Subtracting the two equations we get

V_a-V_w-V_a-V_w=460-540\\\Rightarrow -2V_w=-80\\\Rightarrow V_w=40\ km/h

Applying the value of velocity of wind to the first equation

V_a-40=460\\\Rightarrow V_a =500\ km/h

∴ Velocity of airplane in still air is 500 km/h and Velocity of wind is 40 km/h

5 0
3 years ago
A 27-g steel-jacketed bullet is fired with a velocity of 640 m/s toward a steel plate and ricochets along path CD with a velocit
Dmitry [639]

Answer:

F = - 3.56*10⁵ N

Explanation:

To attempt this question, we use the formula for the relationship between momentum and the amount of movement.

I = F t = Δp

Next, we try to find the time that the average speed in the contact is constant (v = 600m / s), so we say

v = d / t

t = d / v

Given that

m = 26 g = 26 10⁻³ kg

d = 50 mm = 50 10⁻³ m

t = d/v

t = 50 10⁻³ / 600

t = 8.33 10⁻⁵ s

F t = m v - m v₀

This is so, because the bullet bounces the speed sign after the crash is negative

F = m (v-vo) / t

F = 26*10⁻³ (-500 - 640) / 8.33*10⁻⁵

F = - 3.56*10⁵ N

The negative sign is as a result of the force exerted against the bullet

6 0
2 years ago
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