4 years ago

What is the empirical formula for C14H28O7?

Chemistry

1 answer:

mrs_skeptik [129]4 years ago

7 0

Answer:

Empirical formula of C4H8O2, is the answer

Explanation:

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Consider the equilibrium: HCOOH(aq) + F-(aq) <----> HCOO-(aq) + HF (aq) Given that the Ka of HCOOH = 1.8 x 10-4 and the Ka

Aleks [24]

Hey there!:

K = Ka * Kb / Kw

Ka = 1.8*10⁻⁴

Kb = 10⁻¹⁴ / 6.8*10⁻⁴

K = 1.8*10⁻⁴ * ( 10⁻¹⁴/ 6.8*10⁻⁴ ) * ( 1 / 10⁻¹⁴ )

K = = 1.8 / 6.8

K = 0.265

Answer A

Therefore:

K is less than on the forward reaction is not favorable .

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4 years ago

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3 years ago

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Ad libitum [116K]

Your protons are correct but it’s 28 neutrons not 27!

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3 years ago

5. Organisms that make their own energy storage molecules are called producers. What process do

Dominik [7]

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3 years ago

How many milliliters of a 0.275 M NaOH solution is required to react with 0.450 L of CO2 gas

padilas [110]

Volume of NaOH required to react = 145.5 ml

<h3>Further explanation</h3>

Reaction

CO₂(g) + 2 NaOH(aq) ⇒Na₂CO₃(aq) + H₂O(l)

The volume of CO₂ : 0.45 L

mol CO₂ at STP (O C, 1 atm) ⇒ at STP 1 mol gas 22.4 L :

$\tt mol~CO_2=\dfrac{0.45}{22.4}=0.02$

From the equation, the mol ratio of CO₂ : NaOH = 1 : 2, so mol NaOH :

$\tt mol~NaOH=\dfrac{2}{1}\times 0.02=0.04$

Then volume of NaOH :

$\tt V=\dfrac{n}{M}\\\\V=\dfrac{0.04}{0.275}\\\\V=0.1455~L\rightarrow 145.5~mL$

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3 years ago

What is the empirical formula for C14H28O7?​

What is the empirical formula for C14H28O7?