1.List one extensive and one intensive property of marker ink.
Intensive property is a property that is independent of the amount of sample such as the color of the ink. Extensive property is the opposite which is dependent to the amount such as volume.
2.Define mixture.
Mixture is a system that contains two or more substances which are agitated but not chemically bonded.
3.Is tap water a heterogeneous or homogenous mixture?
Tap water is a homogenoeus mixture because it has uniform properties in every sample you get.
4.Is isopropyl alcohol (rubbing alcohol) a heterogeneous or homogenous mixture?
I think the rubbing alcohol is a homogeneous mixture since it has uniform properties as well.
Answer:
Ammonium bisulfate/Formula
(NH4)HSO4
Reason to answer:
Mark me brainliest
Answer:
Density, d = 1.779 g/cm³
Explanation:
The density of a material is given by its mass per unit volume.
Here, height of a piece of magnesium cylinder, h = 5.62 cm
Its diameter, d = 1.34 cm
Radius = 0.67 cm
Volume of he cylinder,
![V=\pi r^2 h\\\\\text{Putting the value of r and h, we get :}\\\\V=(\pi \times (0.67)^2\times 5.62)\ cm^3](https://tex.z-dn.net/?f=V%3D%5Cpi%20r%5E2%20h%5C%5C%5C%5C%5Ctext%7BPutting%20the%20value%20of%20r%20and%20h%2C%20we%20get%20%3A%7D%5C%5C%5C%5CV%3D%28%5Cpi%20%5Ctimes%20%280.67%29%5E2%5Ctimes%205.62%29%5C%20cm%5E3)
![d=\dfrac{m}{V}\\\\d=\dfrac{14.1\ g}{(\pi \times (0.67)^2\times 5.62)\ cm^3}\\\\d=1.779\ g/cm^3](https://tex.z-dn.net/?f=d%3D%5Cdfrac%7Bm%7D%7BV%7D%5C%5C%5C%5Cd%3D%5Cdfrac%7B14.1%5C%20g%7D%7B%28%5Cpi%20%5Ctimes%20%280.67%29%5E2%5Ctimes%205.62%29%5C%20cm%5E3%7D%5C%5C%5C%5Cd%3D1.779%5C%20g%2Fcm%5E3)
So, the density of the sample is 1.779 g/cm³.
Answer:
Explanation:
maleic acid ⇒ fumaric acid
ΔHreaction = ΔHproduct - ΔHreactant
ΔHproduct = -1336.0 kJ mol⁻¹
ΔHreactant = - 1359.2 kJ mol⁻¹.
ΔHreaction = -1336.0 kJ mol⁻¹ - ( - 1359.2 kJ mol⁻¹.)
= 1359.2 kJ mol⁻¹ -1336.0 kJ mol⁻¹
= 23.2 kJ mol⁻¹ .
Enthalpy of isomerization from maleic to fumaric acid is 23.2 kJ per mol.
<span><span> I want to say that the correct answer is choice C, become the same temperature.</span></span>
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<span><span>I hope this helps you! :-)</span></span>