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Korvikt [17]
3 years ago
9

You heat two substances, A and B. Both substances change color. When cooled, substance A returns to its original color, but subs

tance B does not. What most likely happened in this situation? A chemical change occurred in both substances. A physical change occurred in substance A, and a chemical change occurred in substance B. A physical change occurred in both substances. A chemical change occurred in substance A, and a physical change occurred in substance B.
Chemistry
1 answer:
ryzh [129]3 years ago
8 0

The reason why A returned to its original color but B did not is because; A  chemical change occurred in substance A, and a physical change occurred in substance B.

A chemical change results in a change in the "composition" of a substance. When the composition of the substance changes, the change is often irreversible.

A physical change does not alter the composition of a substance hence a physical change is easily reversible.

Since A did not return to its former color, it underwent a chemical change while B underwent a physical change since it returned to its former color.

Learn more: brainly.com/question/6284546

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For the reaction: 3 H2(g) + N2(g) <--> 2 NH3(g), the concentrations at equilbrium were [H2] = 0.10 M, [N2] = 0.10 M, and [
masya89 [10]

The equilibrium constant, k of the reaction in which case, the concentrations of the given reactants and products are as indicated is; Choice A; K = 3.1 x 10⁵

<h3>What is the equilibrium constant , k of the reaction as described in the task content?</h3>

It follows from above that the concentrations of the reactants and products are as follows; [H2] = 0.10 M, [N2] = 0.10 M, and [NH3] = 5.6 M at equilibrium.

Hence, the equilibrium constant of the reaction in discuss is;

K = [5.6]²/[0.10]³[0.10]

k = 5.6² × 10⁴

k = 3.136 × 10⁵

K = 3.1 × 10⁵.

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5 0
2 years ago
While you were "sweating" your chemistry test, water vapor evaporates from your body, absorbing 50,000 J of energy. (assume no
TiliK225 [7]

Answer:

\boxed {\boxed {\sf B. \ 22 \ grams}}

Explanation:

We need to use the formula for heat of vaporization.

Q=H_{vap}*m

Identify the variables.

  • The heat absorbed by the evaporating water is the <u>latent heat of vaporization. </u>For water, that is 2260 Joules per gram.
  • Q is the energy, in this problem, 50,000 Joules.
  • m is the mass, which is unknown.

H_{vap}=2260 \ J/g\\Q=50,000 \ J \\

Substitute the values into the formula.

50,000 \ J=2260 \ J/g*m

We want to find the mass. We must isolate the variable, m.

m is being multiplied by 2260 J/g. The inverse operation of multiplication is division. Divide both sides by 2260 J/g.

\frac{50,000 \ J}{2260 \ J/g} =\frac{2260 \ J/g*m}{2260 \ J/g}

\frac{50,000 \ J}{2260 \ J/g} =m

Divide. Note that the Joules (J) will cancel each other out.

\frac{50,000 \ }{2260 \ g} =m

22.1238938 \ g =m

Round to the nearest whole number. The 1 in the tenth place tells us to leave the number as is.

22 \ g \approx m

The mass is about 22 grams, so choice B is correct.

3 0
3 years ago
It takes 2 g of chlorine to sanitize 1,000,000g of water. How much chlorine will it take to sanitize a 40,000-gallon pool? ( 1 g
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Answer:

0.1g (Gallon) of chlorine

Explanation:

<u>Formula</u>

1 gallon = 3.7L; the density of water is 1.0g/ml

<u>Given</u>

2g (gallon) of chlorine to sanitize = 1,000,000g (gallon) of water

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If 2g (gallon) chlorine = 1,000,000g (gallon)

∴, ? chlorine = 40,000

The First step; set up an equation

1000000/2 = 40000/?

The Next step; divide 1 million to 2

1000000 ÷ 2 = 500000

Then, divide the result by 40000

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In the nearest unit that is 0.1

Therefore, it will take 0.1g (gallon) of chlorine to sanitize a 40,000-gallon pool.

7 0
3 years ago
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Answer:

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The intermolecular forces between Na⁺ (ion) and NH₃ (dipole) are ion-dipole forces.

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