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aliya0001 [1]
2 years ago
8

Plz answer my questions​

Chemistry
1 answer:
egoroff_w [7]2 years ago
7 0

Answer:

I don't know the correct answer

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1.31 times 10^-22 / 6.6262 times 10^-34
victus00 [196]
The first answer is -.595454 the second answer is -1.9488
4 0
3 years ago
Which term refers to a small group of atoms that are attached to larger molecules, providing them with specific chemical propert
stepan [7]
Answer: Small groups of atoms that are attached to larger molecules, giving the specific chemical properties, are called functional groups.

explanation: Functional groups are groups of atoms in a molecule that possess the same chemical feature every time it appears in several compounds. There are various types of functional groups and they have the tendency to react in definite ways. Examples include; the ether functional group (consists of an oxygen atom that forms single bonds with two carbon atoms),the alcohol functional group (consists of an oxygen atom that is bonded to one hydrogen atom and one carbon atom), and the amine functional group (consists of a nitrogen atom bonded to some combination of carbons and hydrogens).
5 0
2 years ago
Determine the correct Lewis structure for ammonia (NH3). Note: Hydrogen and nitrogen have one and five valence electrons respect
Tresset [83]
The lewis structure is helpful in showing how the bonding between atoms of a molecule are. The lewis structure of ammonia would be that the nitrogen atom will share three pairs of electron with the three hydrogen atoms leaving nitrogen to have 1 lone pair.<span />
7 0
4 years ago
Assume the molality of isoborneol in your product is 0.275 mol/kg. What is the melting point of your impure sample given that th
aliina [53]

Answer:

168°C is the melting point of your impure sample.

Explanation:

Melting point of pure camphor= T =179°C

Melting point of sample = T_f = ?

Depression in freezing point = \Delta T_f

Depression in freezing point  is also given by formula:

\Delta T_f=i\times K_f\times m

K_f = The freezing point depression constant

m = molality of the sample  = 0.275 mol/kg

i = van't Hoff factor

We have: K_f = 40°C kg/mol

i = 1 (  non electrolyte)

\Delta T_f=1\times 40^oC kg/mol\times 0.275 mol/kg

\Delta T_f=11^oC

\Delta T_f=T- T_f

T_f=T- \Delta T_f=179^oC-11^oC=168^oC

168°C is the melting point of your impure sample.

4 0
3 years ago
A sample of gas (1.9 mol) is in a flask at 21 °c and 697 mm hg. the flask is opened and more gas is added to the flask. the new
garik1379 [7]

To solve this problem, we assume ideal gas so that we can use the formula:

PV = nRT

since the volume of the flask is constant and R is universal gas constant, so we can say:

n1 T1 / P1 = n2 T2 / P2

 

1.9 mol * (21 + 273 K) / 697 mm Hg = n2 * (26 + 273 K) / 841 mm Hg

<span>n2 = 2.25 moles</span>

8 0
3 years ago
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