Answer:
FADH₂ → Q coenzyme → Complex III → c cytochrome → Complex IV → O₂
Explanation:
During oxidative phosphorylation, the electrons from NADH and FADH₂ are combined with O₂ and the energy released in the process is used to synthesize ATP from ADP.
The components of the electron transport chain are located in the internal part of the mitochondrial membrane in eukaryotic cells, and in the cell membrane in bacteria. The transporters in the electron transport chain are organized into four complexes in the inner mitochondrial membrane. A fifth complex then couples these reactions to the ATP synthesis.
Complex II receives the electrons from the succinate, which is an intermediary in the Krebs cycle. These electrons are transferred to the FADH₂ and then to the Q coenzyme. This liposoluble molecule will transport the electrons from Complex II to Complex III. In this complex, the electrons are transferred from the <em>b</em> cytochrome to the <em>c</em> cytochrome. This <em>c </em>cytochrome, which is a peripheric membrane protein located in the external part of the inner membrane, then transports the electrons to Complex IV where finally they are transferred to the oxygen.
The correct answer to this question is Water will move from left to right.
Water tends to move over to the side where there is less water.
For example,
if there's less water on the RIGHT side,
then the water will tend to move from left, to RIGHT. It <span>shows more solute molecules on the right, so water will move to this side by osmosis. I think it is to do with entropy and the tendency for systems to move to equilibrium if there is an increase in entropy</span>
Answer:
covalent bond, also called a molecular bond, is a chemical bond that involves the sharing of electron pairs between atoms
the sharing of electrons allows each atom to attain the equivalent of a full outer shell, corresponding to a stable electronic configuration.
Explanation:
RNA is made of monomers called nucleotides
Answer:
0.053 M is the concentration of X after 196 seconds.
Explanation:
Initial concentration of the X = ![[A_o]=1.0 M](https://tex.z-dn.net/?f=%5BA_o%5D%3D1.0%20M)
Time taken by the sample, t = 196 s
Final concentration of the X after t = [A] =?
Rate constant of the reaction = k = 
Formula used :
![[A]=[A_o]\times e^{-kt}](https://tex.z-dn.net/?f=%5BA%5D%3D%5BA_o%5D%5Ctimes%20e%5E%7B-kt%7D)
where,
Now put all the given values in this formula, we get
![[A]=[1.0M]\times e^{-1.50\times 10^{-2} s^{-1}\times 196 s}](https://tex.z-dn.net/?f=%5BA%5D%3D%5B1.0M%5D%5Ctimes%20e%5E%7B-1.50%5Ctimes%2010%5E%7B-2%7D%20s%5E%7B-1%7D%5Ctimes%20196%20s%7D)
![[A]=0.053 M](https://tex.z-dn.net/?f=%5BA%5D%3D0.053%20M)
0.053 M is the concentration of X after 196 seconds.
