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Lerok [7]
3 years ago
8

Write 3 examples of units for TIME:

Physics
2 answers:
prisoha [69]3 years ago
8 0

Answer:

The most common units are the second, defined in terms of an atomic process; the day, an integral multiple of seconds; and the year, usually 365 days. The other units used are multiples or divisions of these three.

Explanation:

<h3><em>hope</em><em> </em><em>it</em><em> </em><em>is</em><em> </em><em>helpful</em><em> </em><em>for</em><em> </em><em>you</em><em> </em></h3><h3><em>keep</em><em> </em><em>smiling</em><em> </em></h3>
Mice21 [21]3 years ago
6 0

Answer: Defined in terms of an atomic process; the day, an integral multiple of seconds; and the year, usually 365 day

Explanation:

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Satellite A is orbiting Earth at an altitude of 500 km and Satellite B is orbiting 800 km above the surface . How does the veloc
sp2606 [1]

The velocity of Satellite A is 2% greater than velocity of satellite B.

The given parameters;

  • <em>Altitude of Satellite A = 500 km</em>
  • <em>Altitude of Satellite B = 800 km</em>

The forces acting on the Satellites are given as follows;

F_c = \frac{mv^2}{r} \\\\F_g = \frac{GMm}{r^2} \\\\\frac{v^2}{r}  = \frac{GM}{r^2}\\\\v^2 = \frac{GM}{r} \\\\v^2 r = GM\\\\v_1^2 r _1 = v_2^2 r_2\\\\v_A^2r_A = v_B^2 r_B\\\\(\frac{v_A}{v_B} )^2 = \frac{r_B}{r_A} \\\\\frac{v_A}{v_B}  = \sqrt{\frac{r_B}{r_A} } \\\\\frac{v_A}{v_B}  = \sqrt{\frac{(800,000\  + \ 6.4 \times 10^6}{(500,000\  + \ 6.4 \times 10^6} )} \\\\\frac{v_A}{v_B}  =  1.02 \\\\v_A = 1.02 \ v_B

v_A = v_B( 100\% \ + 2\%)\\\\v_A = 100\%v_B \ + \ \ 2\% v_B\\\\v_A = v_B \ \ + \ 2\% v_B

Thus, the velocity of Satellite A is 2% greater than velocity of satellite B.

Learn more about velocity of satellite here: brainly.com/question/13981089

4 0
3 years ago
The micrometer (1 μm) is often called the micron. (a) How many microns make up 3.0 km? (b) How many centimeters equal 3.0 μm? (c
Tomtit [17]

Answer:

3 x 10⁻⁹km

3 x 10⁻⁴cm

2.73 x 10⁶μm

Explanation:

 A micron is a subunit of measurement usually for length dimensions.

                     1μm   = 1 x 10⁻⁶m

a. How many microns make up 3km;

         Now convert to meter first;

                 1000m  = 1km

           So, 3km will be made up of 3000m

So;

          1 x 10⁻⁶m    =     1μm  

         3000m  =   \frac{3000}{1 x 10^{-6} }   = \frac{3  x 10^{3} }{ 1  x  10^{-6} }   = 3 x 10⁻⁹km

b.  How many centimeters equal 3.0 μm?

            Since;

                        1μm   = 1 x 10⁻⁶m

                         3μm  = 3 x 1 x 10⁻⁶  = 3 x 10⁻⁶m

So;

            100cm  = 1m;

                  1m  = 100cm

             3 x 10⁻⁶m  = 3 x 10⁻⁶  x 10²   = 3 x 10⁻⁴cm

c. How many microns are in 3.0 yd?  

              1yd  = 0.91m

              3yd  = 3 x 0.91  = 2.73m

So;

            1 x 10⁻⁶m    =     1μm  

              2.73m will give \frac{2.73}{1 x 10^{-6} }   = 2.73 x 10⁶μm

           

3 0
3 years ago
Estimate the order of magnitude of the length in meters of each of the following: a. a ladybug b. your leg c. your school buildi
sukhopar [10]
The order of the magnitude of the length in meters is estimated based on the average length of the object: if it is a small object then the unit would be cm and if it is a long object (like a road or something) the distance can be measured in km. Then we convert the unit we measured in into the SI unit of the meter.

Based on this, for the mentioned objects, the estimated length would be as follows:
a- ladybug: 10^-2 meters
b- your leg : 10^0 meters
c- your school building : 10^1 to 10^2 meters
d- a giraffe: 10^0 meters
e- city block: 10^2 meters
4 0
3 years ago
Two charges are located in the xx–yy plane. If q1=−4.10 nCq1=−4.10 nC and is located at (x=0.00 m,y=1.080 m)(x=0.00 m,y=1.080 m)
Gala2k [10]

Answer:

Explanation:

Due to first charge , electric field at origin will be oriented towards - ve of y axis.

magnitude

Ey = -8.99 x 10⁹ x 4.1 x 10⁻⁹ / 1.08² j

= - 31.6 j N/C

Due to second charge electric field at origin

= 8.99 x 10⁹ x 3.6  x 10⁻⁹ / 1.2²+ .6²

= 8.99 x 10⁹ x 3.6  x 10⁻⁹ / 1.8

= 18 N/C

It is making angle θ where

Tanθ = .6 / 1.2

= 26.55°

this field in vector form

= - 18 cos 26.55 i - 18 sin26.55 j

= - 16.10 i - 8.04 j

Total field

= - 16.10 i - 8.04 j + ( - 31.6 j )

= -16.1 i - 39.64 j .

Ex = - 16.1 i

Ey = - 39.64 j .

8 0
4 years ago
Explain the differences between the geocentric theory of the universe and the heliocentric theory
Margarita [4]

Geocentric Theory

In astronomy, the geocentric model is a superseded description of the Universe with Earth at the center. Under the geocentric model, the Sun, Moon, stars, and planets all orbited Earth

Heliocentric Theory

Heliocentrism is the astronomical model in which the Earth and planets revolve around the Sun at the center of the Solar System. Historically, heliocentrism was opposed to geocentrism, which placed the Earth at the center

G-Theory is the earth is the center of the universe.

H-Theory is the sun is the center of the universe.

8 0
3 years ago
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