2. Which kind of model would you

Chemistry

2 answers:

ivann1987 [24]2 years ago

7 0

Bbbbbbbbbbbbbbbbbbbbb

steposvetlana [31]2 years ago

3 0

Answer:

a. Physical model

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Which factor is a characteristic of an acid?

Elina [12.6K]

anything that turns red litmus paper to blue it is an acid and vice versa is true

4 0

3 years ago

If you burn 53.8 g of hydrogen and produce 481 g of water, how much oxygen reacted?

olga2289 [7]

The reaction:
2 H 2 + O 2 → 2 H 2 O
2 Hydrogen molecules react with 1 Oxygen molecule to create 2 molecules of water.
We have to convert 53.8 g of Hydrogen into moles:
53.8 : 2.02 g / moles = 26.63 moles
2 moles H 2 ↔ 1 mole O 2
26.63 moles H 2 ↔ 13.32 moles O 2
Mass ( O 2 ) = 13.32 moles · 32 g/moles = 426.2 g
Answer: 426.2 grams of Oxygen.

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2 years ago

What mass of precipitate will be produced from the reaction of 50.0 mL of 2.50 mol/L sodium hydroxide with an excess of zinc chl

amid [387]

2NaOH + ZnCl2 → 2NaCl + Zn(OH)2

Zn(OH)2 is your precipitate.

No. of moles of NaOH = 2.50X50.0÷1000 = 0.125mol

2mol of NaOH reacted to produce 1 mol of Zn(OH)2.

No. of moles of Zn(OH)2 produced when 0.125mol of NaOH reacted

= 0.125 x 1 ÷ 2

= 0.0625mol

Mass of Zn(OH)2 = 0.0625 x [65.4+2(16+1)] = 6.21g

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2 years ago

Consider a new temperature scale (ºa) based on the melting and boiling points of ammonia (nh3) which are taken as 0.0 ºa and 100

Nady [450]

Answer:- 25.0 degree C corresponds to 231 $^0A$ .

Solution:- Let's say the two temperature scales have linear relationship. The equation of line is:

$y=mx+c$

where, m is the slope of the line and c is the intercept. Let's take the new temperature scale, $^0A$ for y and $^0C$ as $x$ . The equation would be looking as:

$^0A=m*^0C+c$

melting point of ammonia in new scale is 0.0 $^0A$ and in celsius scale it is -77.7 degree C. Boiling point in new scale is 100.0 $^0A$ and in celsius scale it is -33.3 degree C.

Let's plug in the values in the equation of line for melting points and boiling points to make two equations that we would solve:

For melting point:- $0.0=m(-77.7)+c$

For boiling point:- $100=m(-33.3)+c$

Now, we solve these two equations to find out the slope of the equation that is the value of m. Let's multiply the second equation by negative means changing all the signs from negative to positive and vice versa.

$0.0=m(-77.7)+c$

$-100=m(+33.3)-c$