<h3>Answer:</h3>
89.6 L of O₂
<h3>Solution:</h3>
The balanced chemical equation is as,
CH₄ + 2 O₂ → CO₂ + 2 H₂O
As at STP, one mole of any gas (Ideal gas) occupies exactly 22.4 L of Volume. Therefore, According to equation,
44 g ( 1 mol) CO₂ is produced by = 44.8 L (2 mol) of O₂
So,
88 g CO₂ will be produced by = X L of O₂
Solving for X,
X = (88 g × 44.8 L) ÷ 44 g
X = 89.6 L of O₂
Answer:
Given equation of parabola is
and
2
=64x ......(i)
The point at which the tangent to the curve is parallel to the line is the nearest point on the curve.
On differentiating both sides of equation (i), we get
2 y
dx
d y
=64
⇒
dx
d y
=
and
32
Also, slope of the given line is −
3
4
∴−
3
4
=
and
32
⇒and=−24
From equation (i), (−24)
2
=64x⇒x=9
∴ the required point is (9,−24)
Explanation:
This is the correct answer you want
please follow the
The answer is
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Polar will always have the higher boiling point because they have strong van der waal forces
We have to get the relationship between metallic character and atomic radius.
Metallic character increases with increase in atomic radius and decrease with decrease of atomic radius.
If electrons from outermost shell of an element can be removed easily, that atom can be considered to have more metallic character.
With increase in atomic radius, nuclear force of attraction towards outermost shell electron decreases which facilitates the release of electron.
With decrease in atomic radius, nuclear force of attraction towards outermost shell electrons increases, so electrons are hold tightly to nucleus. Hence, removal of electron from outermost shell becomes difficult making the atom less metallic in nature.
