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Inessa [10]
2 years ago
15

5 meddi muttasıl örnek

Physics
2 answers:
alexandr1967 [171]2 years ago
5 0

Answer:

WHAT'S YOUR LANGUAGE

I CAN'T UNDERSTAND

My name is Ann [436]2 years ago
4 0

Answer:

please translate it.i can't understand it..

You might be interested in
a man hits a gold ball (0.205kg) which accelerates at a rate of 20.0 m/s squared. what is the amount of force acted on the ball
Schach [20]

Answer:

<h2>4.1 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 0.205 × 20

We have the final answer as

<h3>4.1 N</h3>

Hope this helps you

7 0
3 years ago
Two parallel-plate capacitors have the same plate area. Capacitor 1 has a plate separation twice that of capacitor 2, and the qu
Luba_88 [7]

Answer:

V_1=8 V_2

Explanation:

Given that:

  • Area of the plate of capacitor 1= Area of the plate of capacitor 2=A
  • separation distance of capacitor 2, d_2=d
  • separation distance of capacitor 1, d_1=2d
  • quantity of charge on capacitor 2, Q_2=Q
  • quantity of charge on capacitor 1, Q_1=4Q

We know that the Capacitance of a parallel plate capacitor is directly proportional to the area and inversely proportional to the distance of separation.

Mathematically given as:

C=\frac{k.\epsilon_0.A}{d}.....................................(1)

where:

k = relative permittivity of the dielectric material between the plates= 1 for air

\epsilon_0 = 8.85\times 10^{-12}\,F.m^{-1}

From eq. (1)

For capacitor 2:

C_2=\frac{k.\epsilon_0.A}{d}

For capacitor 1:

C_1=\frac{k.\epsilon_0.A}{2d}

C_1=\frac{1}{2} [ \frac{k.\epsilon_0.A}{d}]

We know, potential differences across a capacitor is given by:

V=\frac{Q}{C}..........................................(2)

where, Q = charge on the capacitor plates.

for capacitor 2:

V_2=\frac{Q}{\frac{k.\epsilon_0.A}{d}}

V_2=\frac{Q.d}{k.\epsilon_0.A}

& for capacitor 1:

V_1=\frac{4Q}{\frac{k.\epsilon_0.A}{2d}}

V_1=\frac{4Q\times 2d}{k.\epsilon_0.A}

V_1=8\times [\frac{Q.d}{k.\epsilon_0.A}]

V_1=8 V_2

6 0
3 years ago
Define SI unit of measurement.​
ivanzaharov [21]

Answer:

the group of units suggested by the international convention of scientists in 1960 AD to make similarties in meseurment all over the world is called SI units

3 0
2 years ago
Two children are riding on a merry-go-round that is rotating with a constant angular speed. Abbie is one meter from the center o
klio [65]

Answer:

The acceleration of Abbie is half of the Zak's.

Explanation:

The centripetal acceleration of an object on a circular path is given by :

a=r\omega^2

Two children are riding on a merry-go-round that is rotating with a constant angular speed. Let r_1 is distance of Abbie from the merry-go-round and r_2 is distance of Zak's from the merry-go-round. Acceleration of Abbie is :

a_1=r_1\omega^2 ...... (1)

r_1=1\ m

Acceleration of Zak's is :

a_2=r_2\omega^2 .......(2)

r_2=2\ m

Dividing equation (1) and (2) we get :

\dfrac{a_1}{a_2}=\dfrac{r_1}{r_2}\\\\\dfrac{a_1}{a_2}=\dfrac{1}{2}\\\\a_1=\dfrac{a_2}{2}

So, the acceleration of Abbie is half of the Zak's.

7 0
3 years ago
En una librería un libro de 0.6 kg colocado inicialmente en un estante a 40 cm del suelo fue movido a otro estante con una altur
jeyben [28]

Considerando la definición de energía potencial:

  • la energía potencial del libro inicialmente es 2,3544 J y luego de ser movido a otro estante es 7,6518 J.
  • el cambio en la energía potencial del libro es 5,2974 J.
<h3 /><h3>Definición de energía potencial</h3>

La energía potencial es la energía que mide la capacidad que tiene un sistema para realizar un trabajo en función de su posición. En otras palabras, esta es la energía que tiene un cuerpo situado a una determinada altura sobre el suelo.

La energía potencial gravitatoria es la energía asociada con la fuerza gravitatoria. Esta dependerá de la altura relativa de un objeto a algún punto de referencia, la masa, y la fuerza de la gravedad.

Entonces para un objeto con masa m, en la altura h, la expresión aplicada a la energía gravitacional del objeto es:

Ep= m×g×h

Donde

  • Ep es la energía potencial en julios (J).
  • m es la masa en kilogramos (kg).
  • h es la altura en metros (m).
  • g es la aceleración de caída en m/s² (aproximadamente 9,81 m/s²).

<h3>Energía potencial en cada lugar</h3>

En primer lugar, se sabe inicialmente del libro:

  • m= 0,6 kg
  • g= 9,81 m/s²
  • h= 40 cm= 0,4 m (siendo 1 cm= 0,01 m)

Entonces, reemplazando en la definición de energía potencial:

Ep1= 0,6 kg× 9,81 m/s²× 0,4 m

Resolviendo:

<u><em>Ep1= 2,3544 J</em></u>

Por otro lado, se sabe los siguientes datos del libro luego de ser movido:

  • m= 0,6 kg
  • g= 9,81 m/s²
  • h= 1,30 m

Entonces, reemplazando en la definición de energía potencial:

Ep2= 0,6 kg× 9,81 m/s²× 1,30 m

Resolviendo:

<u><em>Ep2= 7,6518 J</em></u>

En resumen, la energía potencial del libro inicialmente es 2,3544 J y luego de ser movido a otro estante es 7,6518 J.

<h3>Cambio de energía potencial</h3>

El cambio en la energía potencial del libro será la diferencia entre la energía potencial luego de ser movido y la energía potencial inicial del libro:

ΔEp= Ep2 - Ep1

ΔEp= 7,6518 J - 2,3544 J

<u><em>ΔEp= 5,2974 J</em></u>

Finalmente, el cambio en la energía potencial del libro es 5,2974 J.

Aprende más sobre energía potencial:

brainly.com/question/21370800

brainly.com/question/25163940

brainly.com/question/25960490

3 0
2 years ago
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