Answer:
(a) 2.39 MPa (b) 3.03 kJ (c) 3.035 kJ
Explanation:
Solution
Recall that:
A 10 gr of air is compressed isentropically
The initial air is at = 27 °C, 110 kPa
After compression air is at = a450 °C
For air, R=287 J/kg.K
cv = 716.5 J/kg.K
y = 1.4
Now,
(a) W efind the pressure on [MPa]
Thus,
T₂/T₁ = (p₂/p₁)^r-1/r
=(450 + 273)/27 + 273) =
=(p₂/110) ^0.4/1.4
p₂ becomes 2390.3 kPa
So, p₂ = 2.39 MPa
(b) For the increase in total internal energy, is given below:
ΔU = mCv (T₂ - T₁)
=(10/100) (716.5) (450 -27)
ΔU =3030 J
ΔU =3.03 kJ
(c) The next step is to find the total work needed in kJ
ΔW = mR ( (T₂ - T₁) / k- 1
(10/100) (287) (450 -27)/1.4 -1
ΔW = 3035 J
Hence, the total work required is = 3.035 kJ
Answer:
Answer for the question :
"the two boxcars A and B have a weight of 20 000 Ib and 30 000 Ib, respectively. If they coast freely down the incline when the brakes are applied to all the wheels of car A causing it to skid, determine the force in the coupling C between the two cars. The coefficient of kinetic friction between the wheels of A and the tracks is μk=0.5. The wheels of car B are free to roll. Neglect their mass in calculation."
is explained in the attachment.
Explanation:
The answer is true because if the effect is neglected, the saturation id region is considered true
Answer:
Retail Salespersons
Explanation:
The Bureau of Labor Statistics or the BLS in short is the federal unit or agency of the United States Labor Department. It is the main stats finding agency of the United States federal government in the field of statistics and labor economics.
According to a publication published by the Labor Statistics Bureau, the retail salesperson sector of occupation employed the most people in the U.S. in the year 2010. It provided employment to about 4.2 million people.
Answer:
![D=0.41m](https://tex.z-dn.net/?f=D%3D0.41m)
Explanation:
From the question we are told that:
Discharge rate ![V_r=0.35 m3/s](https://tex.z-dn.net/?f=V_r%3D0.35%20m3%2Fs)
Distance ![d=4km](https://tex.z-dn.net/?f=d%3D4km)
Elevation of the pumping station ![h_p= 140 m](https://tex.z-dn.net/?f=h_p%3D%20140%20m)
Elevation of the Exit point ![h_e= 150 m](https://tex.z-dn.net/?f=h_e%3D%20150%20m)
Generally the Steady Flow Energy Equation SFEE is mathematically given by
![h_p=h_e+h](https://tex.z-dn.net/?f=h_p%3Dh_e%2Bh)
With
![P_1-P_2](https://tex.z-dn.net/?f=P_1-P_2)
And
![V_1=V-2](https://tex.z-dn.net/?f=V_1%3DV-2)
Therefore
![h=140-150](https://tex.z-dn.net/?f=h%3D140-150)
![h=10](https://tex.z-dn.net/?f=h%3D10)
Generally h is give as
![h=\frac{0.5LV^2}{2gD}](https://tex.z-dn.net/?f=h%3D%5Cfrac%7B0.5LV%5E2%7D%7B2gD%7D)
![h=\frac{8Q^2fL}{\pi^2 gD^5}](https://tex.z-dn.net/?f=h%3D%5Cfrac%7B8Q%5E2fL%7D%7B%5Cpi%5E2%20gD%5E5%7D)
Therefore
![10=\frac{8Q^2fL}{\pi^2 gD^5}](https://tex.z-dn.net/?f=10%3D%5Cfrac%7B8Q%5E2fL%7D%7B%5Cpi%5E2%20gD%5E5%7D)
![D=^5\frac{8*(0.35)^2*0.003*4000}{3.142^2*9.81*10}](https://tex.z-dn.net/?f=D%3D%5E5%5Cfrac%7B8%2A%280.35%29%5E2%2A0.003%2A4000%7D%7B3.142%5E2%2A9.81%2A10%7D)
![D=0.41m](https://tex.z-dn.net/?f=D%3D0.41m)