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LenaWriter [7]
2 years ago
11

5. Calcium carbonate decomposes at 12000 C to form carbon dioxide and calcium oxide. If 25 liters of carbon dioxide are collecte

d at 12000 C, what will the volume of this gas be after it cools to 250 C?
6. I have 130 liters of gas in a piston at a temperature of 2500 C. If I cool the gas until the volume decreases to 85 liters, what will the temperature of the gas be?
Chemistry
1 answer:
Anika [276]2 years ago
5 0

Answer:

5)0.53liters

6)1.634.6°c

Explanation:

using \:  charles \: law \\ v1 \div t1 = v2 \div t2

5) v1=25liters, t1=12000°c. v2=?, t2=250°c

v2=(250×25)/12000

v2=6250/12000

v2=0.52liters

6)v1=130,v2=85, t1=2500, t2=?

t2=(85×2500)/130

t2=212500/130

t2= 1634.6°c

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Pls help!! Which statement best describes the type of radioactive decay shown in the model?
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3 years ago
(+)-Carvone and (-)-carvone differ in the orientations of the substituents around which of the following carbon atoms?
myrzilka [38]

Answer:

The correct option is: B. Carbon 5 only

Explanation:

Carvone is a naturally-occurring monoterpenoid consisting of a six-membered cyclic ring. <u>The </u><u><em>carbon-5</em></u><u> of this cyclic ring of Carvone is </u><u><em>chiral, </em></u><u>due to which Carvone exhibits </u><u><em>enantiomerism</em></u><u>.</u>

The two <em>enantiomeric forms</em> of Carvone are: R-(–)-carvone, or L-carvone, and S-(+)-carvone, or D-carvone.

<em><u>These two enantiomeric forms differ in the orientation of the substituents on the chiral carbon-5.</u></em>

<u />

<u>Therefore, the correct option is B. Carbon 5 only.</u>

5 0
3 years ago
Question 6
kompoz [17]

Considering the combined law equation, the new temperature is -244.56 °C or 28.44 K.

<h3>Boyle's law</h3>

Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant: if the pressure increases, the volume decreases while if the pressure decreases, the volume increases.

Mathematically, this law states that the multiplication of pressure by volume is constant:

P×V=k

<h3>Charles's law</h3>

Charles's law states that the volume is directly proportional to the temperature of the gas: if the temperature increases, the volume of the gas increases while if the temperature of the gas decreases, the volume decreases.

Mathematically, Charles' law states that the ratio of volume to temperature is constant:

\frac{V}{T} =k

<h3>Gay-Lussac's law </h3>

Gay-Lussac's law states that the pressure of a gas is directly proportional to its temperature: increasing the temperature will increase the pressure, while decreasing the temperature will decrease the pressure.

Mathematically, Gay-Lussac's law states that the ratio of pressure to temperature is constant:

\frac{P}{T} =k

<h3>Combined law equation</h3>

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

\frac{PxV}{T} =k

Considering an initial state 1 and a final state 2, it is fulfilled:

\frac{P1xV1}{T1} =\frac{P2xV2}{T2}

<h3>New temperature</h3>

In this case, you know:

  • P1= 1 atm= 760 mmHg
  • V1= 15 L
  • T1= -30 °C= 243 K (being 0 °C= 273 K)
  • P2= 58 mmHg
  • V2= 23 L
  • T2= ?

Replacing in the combined law equation:

\frac{760 mmHgx15 L}{243 K} =\frac{58 mmHgx23 L}{T2}

Solving:

T2x\frac{760 mmHgx15 L}{243 K} =58 mmHgx23 L

T2 =\frac{58 mmHgx23 L}{\frac{760 mmHgx15 L}{243 K}}

<u><em>T2= 28.44 K= -244.56 °C</em></u>

Finally, the new temperature is -244.56 °C or 28.44 K.

Learn more about combined law equation:

brainly.com/question/4147359

#SPJ1

6 0
1 year ago
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