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LenaWriter [7]
3 years ago
11

5. Calcium carbonate decomposes at 12000 C to form carbon dioxide and calcium oxide. If 25 liters of carbon dioxide are collecte

d at 12000 C, what will the volume of this gas be after it cools to 250 C?
6. I have 130 liters of gas in a piston at a temperature of 2500 C. If I cool the gas until the volume decreases to 85 liters, what will the temperature of the gas be?
Chemistry
1 answer:
Anika [276]3 years ago
5 0

Answer:

5)0.53liters

6)1.634.6°c

Explanation:

using \:  charles \: law \\ v1 \div t1 = v2 \div t2

5) v1=25liters, t1=12000°c. v2=?, t2=250°c

v2=(250×25)/12000

v2=6250/12000

v2=0.52liters

6)v1=130,v2=85, t1=2500, t2=?

t2=(85×2500)/130

t2=212500/130

t2= 1634.6°c

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The protection of internal environment from the harms of fluctuations in external environment is termed as homeostasis.

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Convert 7.680 moles of PtSe to grams
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4 years ago
(b) Which solution has a higher percent ionization of the acid, a 0.10M solution of HC2H3O2(aq) or a 0.010M solution of HC2H3O2(
boyakko [2]

Answer: The percent ionization is higher for 0.010 M solution of HC_2H_3O_2

Explanation:

HC_2H_3O_2\rightarrow H^+C_2H_3O_2^-

 cM           0M           0M

c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

a) Given c= 0.10 M and \alpha = ?

K_a=1.8\times 10^{-5}

Putting in the values we get:

1.8\times 10^{-5}=\frac{(0.10\times \alpha)^2}{(0.10-0.10\times \alpha)}

(\alpha)=0.013

\%(\alpha)=0.013\times 100=1.3\%

b) Given c= 0.010 M and \alpha = ?

K_a=1.8\times 10^{-5}

Putting in the values we get:

1.8\times 10^{-5}=\frac{(0.010\times \alpha)^2}{(0.010-0.010\times \alpha)}

(\alpha)=0.041

\%(\alpha)=0.041\times 100=4.1\%

The percent ionization is higher for 0.010 M solution of HC_2H_3O_2

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3 years ago
An electrically neutral atom of oxygen has eight electrons. What other facts do you know for sure about this atom? 1.) there are
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2.) there are eight protons

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3 years ago
Read 2 more answers
the hcp ordered 0.2 mg of methylergonovine, and the vial contains 0.8 mg/ml. how many ml of methylergonovine should the nurse dr
olasank [31]

The volume (in mL) of methylergonovine the nurse should draw up in the syringeis is 0.25 mL

<h3>What is density? </h3>

The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as

Density = mass / volume

With the concept of density, we can obtain the volume of methylergonovine. Details below

<h3>How to determine the volume </h3>

The following data were obtained from the question:

  • Mass of methylergonovine = 0.2 mg
  • Density of methylergonovine = 0.8 mg/mL
  • Volume of methylergonovine =?

Density = mass / volume

Cross multiply

Density × volume = mass

Divide both sides by density

Volume = mass / density

Volume = 0.2 / 0.8

Volume of methylergonovine = 0.25 mL

Learn more about density:

brainly.com/question/952755

#SPJ1

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