Question

5. Calcium carbonate decomposes at 12000 C to form carbon dioxide and calcium oxide. If 25 liters of carbon dioxide are collected at 12000 C, what will the volume of this gas be after it cools to 250 C?
6. I have 130 liters of gas in a piston at a temperature of 2500 C. If I cool the gas until the volume decreases to 85 liters, what will the temperature of the gas be?

Answer 1

Answer:

5)0.53liters

6)1.634.6°c

Explanation:

$using \: charles \: law \\ v1 \div t1 = v2 \div t2$

5) v1=25liters, t1=12000°c. v2=?, t2=250°c

v2=(250×25)/12000

v2=6250/12000

v2=0.52liters

6)v1=130,v2=85, t1=2500, t2=?

t2=(85×2500)/130

t2=212500/130

t2= 1634.6°c